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Sindrei [870]
2 years ago
5

SUMA Y RESTA DE FRACCIONES

Mathematics
1 answer:
Kitty [74]2 years ago
8 0

Answer:

  • Camila y Hania fueron las que comieron más pastel
  • Entre las tres comieron \frac{5}{6} de pastel
  • Sobró \frac{1}{6} de pastel

Step-by-step explanation:

La pregunta está mal formulada. Debería ser :

A Valentina le tocó 1/6 , a Camila 1/3 y a Hania 2/6 del pastel.

Para responder a la pregunta de quién comió más pastel podemos proceder de varias formas.

Una forma es expresar las fracciones de manera decimal :

Valentina : \frac{1}{6}=0.1666

Camila : \frac{1}{3}=0.3333

Hania : \frac{2}{6}=0.3333

Así nos daríamos cuenta de que Camila y Hania fueron las que comieron más pastel (Vale aclarar que Camila y Hania comieron la misma cantidad).

Otra posible forma es igualando los denominadores de las fracciones y comparando sus numeradores.

Por ejemplo, \frac{1}{3} se puede expresar como \frac{1}{3}=\frac{2}{6} (multiplicamos por dos tanto al numerador como al denominador) ⇒ las nuevas fracciones correspondientes a lo que comió cada una son :

Valentina : \frac{1}{6}

Camila : \frac{2}{6}

Hania : \frac{2}{6}

Dado que todas las fracciones tienen el mismo denominador (seis) comparamos ahora sus numeradores y nos damos cuenta de nuevo que Camila y Hania fueron las que comieron más pastel.

Con las tres fracciones con el mismo denominador (seis) procedemos a responder la segunda pregunta :

¿Qué fracción de pastel comieron entre las tres?

Para averiguarlo sumaremos las fracciones de pastel que comió cada una :

\frac{1}{6}+\frac{2}{6}+\frac{2}{6}=\frac{5}{6}

Encontramos que entre Valentina, Camila y Hania comieron \frac{5}{6} de pastel.

Finalmente, para averiguar que fracción de pastel sobró debemos restarle al total (uno) la fracción de pastel que comieron entre las tres :

1-\frac{5}{6}=\frac{1}{6}

Esto se debe a que el ''uno'' representa el ciento por ciento del pastel (el total). Encontramos que sobró \frac{1}{6} de pastel.

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Read 2 more answers
Pls solve part b) iii thanks
Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees

Read more about bearings at:

brainly.com/question/24142612

#SPJ1

4 0
2 years ago
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