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chubhunter [2.5K]
3 years ago
8

How do I find the value of x?

Mathematics
1 answer:
3241004551 [841]3 years ago
5 0
The value of x, bring the variable to the left side and bring all the remaining values to the right side. Simplify the values to find the result.
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Nate mother drives 225 miles to work each month how many miles do she drives in one year show work
Lubov Fominskaja [6]

Answer:

2700

Step-by-step explanation:

7 0
3 years ago
Someone give me the answers to this
strojnjashka [21]
Range: the set of all y-values of a graph or equation.

Y-intercept: the y-value where the graph intersects the y-axis.

Domain: the set of all x-values of a graph or equation.

X-intercept: the x-values where the graph intersects the x-axis.

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
Find the value of (+328.62) – (+98.6). A. 230.02 B. 427.22 C. –427.22 D. –230.02
Jet001 [13]

Answer:

Option A - (+328.62)-(+98.6)=230.02

Step-by-step explanation:

We have given the expression (+328.62)-(+98.6)

We have to find the value of the expression ?

Solution :

Step 1 - Write the expression

=(+328.62)-(+98.6)

Step 2 - Applying symbol rule i.e. multiplication of positive into negative is always negative, (-)(+)=(-)

=328.62-98.6

Step 3 - Solve

=230.02

Therefore, The value of the expression is (+328.62)-(+98.6)=230.02

So, Option A is correct.

7 0
3 years ago
The Smith family went out to eat at Applebees. The total for their meal was $58.25. If they want to leave a 20%, how much tip sh
Len [333]

Answer:

$11.65

Step-by-step explanation:

20% of 58.25, "of" in math means multiplication. So you multiply it.

To get 20% as a fraction you move the decimal 2 places to the left, and it's .2 or .20 so you get this equation:

.20 * 58.25

So your answer is, $11.65.

To find the total of the bill including the tip it would just be

11.65 + 58.25 = 69.90

4 0
3 years ago
Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$
Viktor [21]

When n=0, we have

5^{3^0} + 1 = 5^1 + 1 = 6

3^{0 + 1} = 3^1 = 3

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for n=k, that

3^{k + 1} \mid 5^{3^k} + 1

Now for n=k+1, we have

5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)

so we know the left side is at least divisible by 3^{k+1} by our assumption.

It remains to show that

3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1

which is easily done with Fermat's little theorem. It says

a^p \equiv a \pmod p

where p is prime and a is any integer. Then for any positive integer x,

5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3

Furthermore,

5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3

which goes all the way down to

5^{3^k} \equiv 5 \pmod 3

So, we find that

\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3

QED

5 0
1 year ago
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