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3 years ago

An equation is shown below:

2 answers:

7 0

First you distribute the 2 to the X and the -7 so the equation becomes 8x+2x-14=7x+3x-14 you then combine like terms and the equation becomes 10x-14=10x-14. you then add 14 to one side and get 10x=10x+0 or just 10x=10x, and then you subtract 10x from both sides and get 0, no solutions.

b) you used the distributive property in the begining of solving the equation.

Lostsunrise [7]3 years ago

3 0

8x + 2x - 14 = 7x +3x - 14
10x - 14 = 10x - 14
+ 14 + 14
-------- ---------
0 0
10x = 10x + 0
-10x -10x
------ ------
0x = 0
--- ----
0 0

x = 0
Error actually
bc you can't have 0x
but x = 0 still

Remove brackets
Gather like terms
Get rid of the lone number
Transfer
Divide

Check answer:
8x + 2(x -7) = 7x + 3x -14
(8*0) + 2(0 - 7) = (7*0) + (3*0) - 14
0 + (2*-7) = 0 + 0 - 14
- 14 = - 14
which is true, so x = 0

It was a trippy question tho ;)

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4 years ago

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You are running a race. The probability that you win is 3/5. What is the probability that you lose at most 2 out of your 6 races

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Answer:

The probability that you lose at most 2 out of your 6 races is 0.54432.

Step-by-step explanation:

We are given that you are running a race. The probability that you win is 3/5.

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The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 6 races

r = number of success = at most 2 lost

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you lose a race = 1 - (3/5) = 2/5 or 0.4

Let X = Number of races lost

So, X ~ Binom(n = 6, p = 0.40)

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P(X $\leq$ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= $\binom{6}{0} \times 0.40^{0} \times (1-0.40)^{6-0} + \binom{6}{1} \times 0.40^{1} \times (1-0.40)^{6-1} + \binom{6}{2} \times 0.40^{2} \times (1-0.40)^{6-2}$

= $1 \times1 \times 0.60^{6} + 6 \times 0.40^{1} \times 0.60^{5} +15\times 0.40^{2} \times 0.60^{4}$

= 0.54432

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3 years ago