Given the following data, what is the probability that a car will have a V8 or a manual transmission?

In triangle ABC if AE, BF, and CD are the medians and AE and BF intersect at the point (2,3) at what point does CD intersect AE?

grin007 [14]

So the problem ask to calculate the point where the CD intersect where as in the triangle ABC and AE, BR, CD are the median and AE and BF intersect at a certain point. The best answer among the question is letter D. (2,3)

3 0

3 years ago

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During a high school basketball season, Casey successfully made 18 of the 25 free throws she attempted. What is her percentage o

Galina-37 [17]

Answer:

72%

Step-by-step explanation:

Basket she made successfull = 18/25

Percentage = 18/25 x 100 = 72%

7 0

3 years ago

Kate has a new beaded necklace. 25% of the 76 beads on Kate's necklace are blue. How many blue beads are there on Kate's necklac

Colt1911 [192]

0.25x76=19 blue beads which are on Kate’s necklace.

5 0

3 years ago

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michaela spent $33 on 3 rose bushes and 3 pots of ivy. totsakan spent $92 on 12 rose bushes and 4 pots of ivy. find the cost of

Eva8 [605]

Answer:

One rose bush costs $6

One pot of ivy costs $5

Step-by-step explanation:

Set up an equation:

Variable x = cost of rose bushes

Variable y = cost of pots of ivy

3x + 3y = 33

12x + 4y = 92

I will use substitution to first solve for x:

3y = 33 - 3x

Divide both sides by 3

y = 11 - x

Substitute y value for 11 - x:

12x + 4(11 - x) = 92

Use distributive property

12x + 44 - 4x = 92

Combine like terms

8x + 44 = 92

8x = 48

Divide both sides by 8

x = 6

Solve for y by plugging in 6 for the x value:

3(6) + 3y = 33

18 + 3y = 33

3y = 15

Divide both sides by 3

y = 5

Check work:

3(6) + 3(5) = 33

18 + 15 = 33

33 = 33

Correct

3 0

3 years ago

How do you simplify this trigonometric expression? <img src="https://tex.z-dn.net/?f=%5Cfrac%7Btan%28%5Calpha%29%20%7D%7Bsec%28%

Julli [10]

Answer:

csc(α)

Step-by-step explanation:

We are given $\frac{tan(\alpha) }{sec(\alpha)-cos(\alpha ) }$ .

One key trick when dealing with trig is to write all the functions in terms of cosine and sine.

Tangent (tan) is sine / cosine, secant (sec) is 1 / cosine. So, replace these:

$\frac{tan(\alpha) }{sec(\alpha)-cos(\alpha ) }=\frac{\frac{sin(\alpha )}{cos(\alpha )} }{\frac{1}{cos(\alpha) }-cos(\alpha ) }$

In the denominator, let's find a common denominator and subtract those:

$\frac{1}{cos(\alpha )} -cos(\alpha )=\frac{1}{cos(\alpha) } -\frac{cos^{2} (\alpha) }{cos(\alpha) } =\frac{1-cos^2(\alpha) }{cos(\alpha) }$

Remember the trig identity that sin²(α) + cos²(α) = 1, so we know that 1 - cos²(α) = sin²(α). Plug this into the equation:

$\frac{1-cos^2(\alpha) }{cos(\alpha) }=\frac{sin^2(\alpha )}{cos(\alpha) }$

We now have [sin(α)/cos(α)] / [sin²(α)/cos(α)]. The cos(α) in the top and bottom cancel out, and we are left with sin(α) / sin²(α) = 1 / sin(α).

Remember that cosecant is the opposite of sine, so 1/sin(α) = csc(α).

<em>~ an aesthetics lover</em>

4 0

4 years ago