1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Monica [59]
3 years ago
5

recipe for sparkling grape juice calls for 5/8 quarts of sparkling water and 1/5 quarts of grape juice how much sparkling water

would you need to mix with 6 quarts of grape juice?
Mathematics
1 answer:
ohaa [14]3 years ago
3 0

You would need 18 3/4 quarts of sparkling water.

You might be interested in
Cameras R Us has a sale for 25% off camera bags, which is a discount of $20. To find the original cost of the camera bag, Tara c
Vsevolod [243]

Answer:

It will be 2. (B) and 4. (D)

Step-by-step explanation:

I took the assignment and got it right :D

6 0
3 years ago
Read 2 more answers
Como simplificar 120/45
Leto [7]

Answer:

simplified in the exact form: 8/3

simplified in decimal form: 2.6

simplified in mixed number form:  2 2/3

5 0
3 years ago
6. RVHS sold 143 Adult and Student tickets to the
slava [35]

Answer:

57 adult tickets, 86 student tickets

7 0
2 years ago
Use the number line to find the equivalent fraction
kifflom [539]
I think that the Equivalent fraction is 6/8
3 0
3 years ago
Read 2 more answers
A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
Other questions:
  • Suppose that the perimeter a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width ractangle, in f
    10·1 answer
  • How can you write a fraction as a decimal?
    15·1 answer
  • The product of 8 and x plus the quotient of y and 7. answer choices are (8 + x)/(7 + y) (8x) + (y/7) (8 + x)(y/7)
    7·1 answer
  • Which statement describes the graph of the number of apples in the bag?
    13·1 answer
  • Perform the following division:
    15·2 answers
  • Round 8,624 to the nearest thousand
    13·2 answers
  • Find the inverse of (-3,2),(-1,8),(1,14),(3,20)
    5·1 answer
  • I need some help pls thx
    9·1 answer
  • Please help quick!!
    13·2 answers
  • HELP I WILL GIVE 30 POINTS AND MARK BRAINLIEST
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!