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Minchanka [31]
3 years ago
12

LOOK AT THE PHOTO PLEASE

Mathematics
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

The answer to the question provided is 11.

Step-by-step explanation:

\:  \:  \:  \:  \: 5x + 9 = 6x - 2 \\  \frac{ - 5x \:  =   - 5x }{9  = 1x - 2}  \\  \frac{ + 2  \:  \:  \:  \: =  + 2}{ \frac{11}{1} =  \frac{1x}{1}  }  \\ 11 = x

[I apologize if the answer to the question provided is inaccurate]

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Find the equation of the line which passes through the point (7,2) and is perpendicular to y=5x-2
MariettaO [177]

Answer:

\displaystyle y=-\frac{1}{5}x+\frac{17}{5}

Step-by-step explanation:

<u>Equation of a line</u>

A line can be represented by an equation of the form

y=mx+b

Where x is the independent variable, m is the slope of the line, b is the y-intercept and y is the dependent variable.

We need to find the equation of the line passing through the point (7,2) and is perpendicular to the line y=5x-2.

Two lines with slopes m1 and m2 are perpendicular if:

m_1.m_2=-1

The given line has a slope m1=5, thus the slope of our required line is:

\displaystyle m_2=-\frac{1}{m_1}=-\frac{1}{5}

The equation of the line now can be expressed as:

\displaystyle y=-\frac{1}{5}x+b

We need to find the value of b, which can be done by using the point (7,2):

\displaystyle 2=-\frac{1}{5}*7+b

Operating:

\displaystyle 2=-\frac{7}{5}+b

Multiplying by 5:

10=-7+5b

Operating:

10+7=5b

Solving for b:

\displaystyle b=\frac{17}{5}

The equation of the line is:

\boxed{\displaystyle y=-\frac{1}{5}x+\frac{17}{5}}

7 0
3 years ago
If x &gt; y, then |x| &gt; |y|. This conditional statement is (true or false) . Counterexample:
Mademuasel [1]
x=1
y=-2

x>y is true, but |x|=1 and |y|=2, but 1>2 is false.
3 0
3 years ago
In figure AB and CD bisect each other at O. State the 3 pairs of equal parts in ∆AOC and ∆BOD. Is ∆AOC ≅ ∆BOD? Give reasons
GuDViN [60]

Answer:

SEE EXPLANATION

Step-by-step explanation:

In\:\triangle AOC \:\&\:\triangle BOD

AO \cong OB.... (given)

\angle AOC \cong\angle BOD

(vertical \: \angle s)

CO \cong OD.... (given)

\therefore \triangle AOC \:\cong\:\triangle BOD

(SAS \: postulate)

So, the 3 pairs of equal parts in ∆AOC and ∆BOD are:

AC = BD

m\angle OAC = m\angle OBD

m\angle OCA = m\angle ODB

7 0
3 years ago
BRAINLIEST ASAP! PLEASE ANSWER!!!!!
kenny6666 [7]
Similarities: They both are polynomials of degree 2, both of their graphs is a parabola, both have either 2 or 0 real solutions, they are both continuous functions over R 

<span>(DOS= difference of two squares, PST=perfect square trinomial </span>

<span>Differences: PST has three terms, whereas the difference of squares has 2. PST's factors are both the same, whereas DOS's elements are conjugates of each other. DOS can always be factored into two distinct polynomials with rational coefficients, whereas PST has two same polynomial factors.</span>
8 0
3 years ago
294 students went on a field trip. Five buses were filled and 14 students travelled in cars. How many students were in each bus?
Irina-Kira [14]

Answer:

294 - 14 = 280 ÷ 5 = 56

In conclusion, there were 56 Students in each Bus.

3 0
3 years ago
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