Answer: so i think for part a , the first term is a subscrpit 0 which is 10. Then the formula for any term in the sequence is Ao x R ^n. So R =2 so
1st term = 10 ( 2^0)= 1
2nd term = 10 (2^1) =20
3rd term = 10 (2^2)= 40
4th = 80
5th = 160
Part B
The limit as n approaches infinity for a sub n when R is 0, 1 and 2. THE LIMIT FOR R of 0, 1 and 2 is infinity.
Part C...i will have to research...sorry
Step-by-step explanation:
30 x 28= 840
It's would beat 840 times in half an hour.
84/4=21
now take the 2 even numbers below 21 and the 2 even numbers above 21
18 +20 + 22 +24 = 84
the numbers are 18, 20, 22 & 24
3a+b+c
The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.
So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:
16a+8b-6c - 2*(5a+3b-4c) =
16a+8b-6c -10a-6b+8c =
6a+2b+2c
half of that is
(6a+2b+2c)/2 = 3a+b+c
Hello :
f(x) = <span>√x+5)
x+5 </span>≥ 0 ... x <span>≥ -5
</span>domain is : [,-5 ; <span>+ ∞<span> [</span></span>
