Please help ASAP!!!!!!!!!

What is the width (or height) of the parking lot?

Gre4nikov [31]

The width is 146.0315533981 cuz 12033÷82.4 is 146.0315533981

6 0

3 years ago

If P and Q are two sets then n( P-Q) means ?

Lapatulllka [165]

$\huge{\mathbb{ \tt{ANSWER}}}$

I shall use the symbol U for union

^ for intersection

~ for complement

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

8 0

3 years ago

2-11/12 in simplest form =

lisov135 [29]

If you are trying to subtract 11/12 from 2 then the answer would be 13/12 as a improper fraction and 1 1/12 as a mixed number

3 0

4 years ago

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Let AB // ED , AB = 10 units, AC = 12 units, and DE = 5 units. What is the length of AD?

zheka24 [161]

Answer:

length of CD = 18 units.

Step-by-step explanation:

In ΔABC and ΔCED,

AB║DE and AD is a transversal line,

m∠ABC = m∠CED [Alternate interior angles]

m∠ACB = m∠DCE [Vertically opposite angles]

ΔABC ~ ΔCED [By AA property of similarity]

Therefore, by the property of similar triangles, corresponding sides will be proportional.

$\frac{AB}{DE}= \frac{AC}{DC}$

$\frac{10}{5}=\frac{12}{CD}$

CD = 6

Since, AD = AC + CD

AD = 12 + 6

= 18 units

Therefore, length of CD = 18 units.

4 0

3 years ago

explain what does the constant rate of change means in the context, (basically what is the meaning of a constant rate change.).

LUCKY_DIMON [66]

Here the topic is "functions." Roughly speaking, we have a box. Input enters at one end and output exists at the other. Now, if every input value x (such as 2) is doubled by the box, every output value is 2x: (0,0), (1,2), (2,4), etc.

We call this "doubling" a "constant rate of change.

If you plot the points given, you'll see that they all are on a straight line. That straight line has the slope 2: y = 2x. Again, 2 is the "constant rate of change" here.

If you drive at a steady 55 mph, you are covering 55 miles during every hour behind the wheel. Again, 55 is a "constant rate of change."

4 0

3 years ago

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