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3 years ago

What’s the answer?? help

Mathematics

1 answer:

viva [34]3 years ago

6 0

5/7. Use rise over run it helps

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Two acute triangles are similar. Which of the following must the similar triangle have?

abruzzese [7]

B is the only one that makes sense if you break them each down. An Acute doesnt have every Pair of angles congruent, the don't have to have proportional side lengths, and it can't have a right angle or it would be a right triangle.

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2 years ago

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What is the value of f (x) = x (to the second power) - 6 evaluated for x = -2?

katrin [286]

I hope this helps you

8 0

2 years ago

Find AC What Is The Equation To AC?

In-s [12.5K]

Given:

Given that ABC is a right triangle.

The length of AB is 7 units.

The measure of ∠A is 65°

We need to determine the length of AC

Length of AC:

The length of AC can be determined using the trigonometric ratio.

Thus, we have;

$cos \ \theta=\frac{adj}{hyp}$

Where the value of $\theta$ is 65° and the side adjacent to the angle is AC and the side hypotenuse to the angle is AB.

Substituting the values, we have;

$cos \ 65^{\circ}=\frac{AC}{AB}$

Substituting AB = 7, we have;

$cos \ 65^{\circ}=\frac{AC}{7}$

Multiplying both sides by 7, we get;

$cos \ 65^{\circ} \times 7=AC$

$0.423 \times 7=AC$

$2.961=AC$

Rounding off to the nearest hundredth, we get;

$2.96=AC$

Thus, the length of AC is 2.96 units.

6 0

3 years ago

Colleen bought a cup of coffee that had 32 ounces in it. She drank 8 ounces of the coffee. What percent of the coffee is left?

Andreas93 [3]

75% is left in the cup

3 0

2 years ago

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Construct a polynomial function with the stated properties. Reduce all fractions to lowest terms. Third-degree, with zeros of −3

RSB [31]

Answer:

$\Large \boxed{-\dfrac{5}{4}(x+3)(x+1)(x-2)}$

Step-by-step explanation:

Hello,

Based on the indication, we can write this polynomial as below, k being a real number that we will have to identify (degree = 3 and we have three zeroes -3, -1, and 2).

$\Large \boxed{k(x+3)(x+1)(x-2)}$

We know that the point (1,10) is on the graph of this function, so we can say.

$k(1+3)(1+1)(1-2)=10}\\\\4*2*(-1)*k=10\\\\-8k=10\\\\k=\dfrac{10}{-8}=-\dfrac{5}{4}$

Then the solution is:

$\large \boxed{-\dfrac{5}{4}(x+3)(x+1)(x-2)}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

8 0

3 years ago