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Orlov [11]
3 years ago
11

A company begins operations in Year 1 and offers a one-year warranty on all products sold. Total appliance sales in Year 1 are $

1,600,000, and the company estimates future warranty costs in Year 2 to be 2% of current sales. Actual warranty costs in Year 2 are $25,000. Also in Year 2, the company has additional sales of $2,400,000 and revises its estimate of warranty costs associated with sales in Year 2 to be 1.5%. Exercise 8-15B Part 4 4. What is the balance in Warranty Liability at the end of Year 1 and Year 2
Business
1 answer:
Aleks04 [339]3 years ago
6 0

Answer: See explanation

Explanation:

Based on the information given in the question, the balance in Warranty Liability at the end of Year 1 and Year 2 will be calculated thus:

Balance in Warranty Liability at the end of Year 1 will be:

= $1,600,000 × 2%

= $1,600,000 × 0.02

= $32,000

Balance in Warranty Liability at the end of Year 2 will be:

= $2,400,000 × 1.5%

= $2,400,000 × 0.015

= $36,000

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Geraldo gauged the level of exposure to his marketing campaign using the percentage of the target population exposed at least on
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Bill and Nancy, managers at Sanzen Inc., want to the check the consistency of results for a performance measure that uses rating
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Inter-rater reliability.

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3 years ago
A woman worked for 30 years before retiring. At the end of the first year of employment she deposited 5000 into an account for h
Mrrafil [7]

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$797,837

Explanation:

the first withdrawal is $50,000

the second is $51,500

and so on...

the formula that used to solve the interest rate earned by the annuity is:

$50,000 x {[(1 + i)³⁰ - (1 + 3%)³⁰] / [(1 + i)³⁰ x (i - 3%)]} x (1 + i) = $5,000 x {[(1 + i)³⁰ - (1 + 3%)³⁰] / (i - 3%)}

we start to simplify the equation by cancelling  {[(1 + i)³⁰ - (1 + 3%)³⁰] / (i - 3%)}

[$50,000 x (1 + i)] / (1 + i)³⁰ = $5,000

now we cancel $5,000 on each side:

[10 x (1 + i)] / (1 + i)³⁰ = 1

now lets take away (1 + i):

10 / (1 + i)²⁹ = 1

things get a little bit more simple now:

10 = (1 + i)²⁹

²⁹√10 = ²⁹√(1 + i)²⁹

1.082636734 = 1 + i

i = 1.082636734 - 1 = 0.082636734 = 8.2636734%

now we replace i in any equation:

= $50,000 x {[(1 + 0.082636734)³⁰ - 1.03³⁰] / [(1 + 0.082636734)³⁰ x (0.082636734 - 0.03)]} x (1 + 0.082636734)

= $50,000 x  {[10.82636738 - 2.427262471] / [10.82636738 x 0.052636734]} x (1 + 0.082636734)

= $50,000 x  {8.399104909 / 0.56986462} x (1.082636734)

= $50,000 x 14.73877236 x 1.082636734

= $797,837

8 0
3 years ago
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