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Marrrta [24]
3 years ago
9

Point B has coordinates ​(4,1). The​ x-coordinate of point A is -4. The distance between point A and point B is 10 units. What a

re the possible coordinates of point​ A?
Mathematics
1 answer:
klasskru [66]3 years ago
7 0

Given:

Point B has coordinates ​(4,1).

The​ x-coordinate of point A is -4.

The distance between point A and point B is 10 units.

To find:

The possible coordinates of point​ A.

Solution:

Let the y-coordinate of point A be y. Then the two points are A(-4,y) and B(4,1).

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The distance between point A and point B is 10 units.

\sqrt{(4-(-4))^2+(1-y)^2}=10

Taking square on both sides, we get

(8)^2+(1-y)^2=100

(1-y)^2=100-64

(1-y)^2=36

Taking square root on both sides, we get

(1-y)=\pm \sqrt{36}

-y=\pm 6-1

y=1\mp 6

y=1-6 and y=1+6

y=-5 and y=7

Therefore, the possible coordinates of point​ A are either (-4,-5) or (-4,7).

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