Answer:
2,826
Step-by-step explanation:
A tenth is the first place value after the decimal point
In this case, 2,826.<u>0</u>0
To round a number to the tenths place, we look at the hundredths place
If the number is 5 or more, we add 1 to the tenths place, and leave the numbers to the right 0's
If the number is 4 or less, we keep the number as it is in the tenths place, and leave the numbers to the right 0's
In this case, the hundredths place is a 0, which is less than 4, so we keep the 0 in the tenths place, and leave the to the right 0's.
Thus, our final answer is 2,826.
Answer:
*read explanation for both questions*
Step-by-step explanation:
So the first one asks <em>”the first number in a pattern is 6, the pattern follows the rule ’</em><em>multiply by 4’ </em><em>“</em>
The question has the answer to it, so each number would be multiplied by 4. So we have the first one which is 6, next we multiply 6 x 4 = 24. Then we multiply 24 x 4 = 96. and finally you multiply 96 x 4 = 384.
That’s the pattern fo the first one
The second one asks <em>“The shapes have been sorted into two groups. explain what attribute was used to sort the shapes.”</em>
<em />
When we’re looking for attributes, look for what they have in common. For me, I see that Group 1 has the smaller versions of the same shapes in Group 2. So that could be the attribute the question is asking for.
Divide the second price by the second pounds. 9.95 / 5 = 1.99
So for every pound you get you pay 1.99 dollars. The second deal is better.
I would have to say 32,4 but i would double check it
Answer:
I = P/(RT)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
P = IRT
<u>Step 2: Solve for </u><em><u>I</u></em>
- [Division Property of Equality] Divide RT on both sides: P/(RT) = I
- Rewrite/Rearrange: I = P/(RT)