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3 years ago

How do i find a37 in an arithmetic sequence of (-12, -5, 2...) ? Also how i do i find the explicit formula for this?

Mathematics

1 answer:

miv72 [106K]3 years ago

7 0

Answer:

Step-by-step explanation:

Look at the differences between terms.

The initial term is -12, and each successive term is 7 more than the preceding term:

a₂ = a₁ + 7

a₃ = a₂ + 7

Etc.

a₁₃ = a₁ + (13-1)7 = -12 + (12)7 = 72

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Find the slope first: 4=x 2=y 1=x2 -7=y2
-7-2/1-4=-9/-3
So the slope is -9/-3
so far we have y=-9/-3x-b
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In a sequence, each number after the first number is obtained by adding 4 to the previous number. If the first number in the seq

fomenos

Answer:

$T_n = 3+ 4n$

Step-by-step explanation:

From the question, we understand that:

$T_1 = 7$ ---- First Term

$d = 4$ ---- Common difference

Required

Determine the nth term

nth term of a sequence is calculated using:

$T_n = T_1 + (n - 1)d$

Substitute values for $T_1$ and $d$

$T_n = 7 + (n - 1) * 4$

Open bracket

$T_n = 7 + 4n - 4$

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$T_n = 7 - 4+ 4n$

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Hence, the nth term of the sequence is:

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Answer:

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