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3 years ago

Graph the line whose y-intercept is 2 and whose x-intercept is -5

Mathematics

1 answer:

Margaret [11]3 years ago

8 0

Answer:

y=2/5x + 2

Step-by-step explanation:

find slope by using formula between these two points: (0,2) and (-5,0); then put into slope-intercept form (y=mx+b)

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Oduvanchick [21]

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1 year ago

Sam said the square root of a rational number must be a rational number. Jenna disagreed. She said that it is possible that the

AveGali [126]

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2 years ago

Read 2 more answers

Type the correct answer for each.

xxTIMURxx [149]

If point $\left(x,\ \frac{\sqrt{7}}{3}\right)$ is on the unit ircle, then:

$x^2+\left( \frac{ \sqrt{7} }{3} \right)^2=1 \\ \\ \Rightarrow x^2+ \frac{7}{9} =1 \\ \\ \Rightarrow x^2=1- \frac{7}{9} = \frac{2}{9} \\ \\ \Rightarrow x= \sqrt{ \frac{2}{9} } = \frac{ \sqrt{2} }{3}$

Since, the point is in the second quadrant, x is negative.

Thus, $(x,\ y)=\left(x,\ \frac{\sqrt{7}}{3}\right)=\left(-\frac{ \sqrt{2} }{3},\ \frac{\sqrt{7}}{3}\right)$

Part A:

$3 \sqrt{7} =6\left( \frac{ \sqrt{7} }{2} \right) \\ \\ =6\left( \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \right) \\ \\ =6\left( \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } \right)=-6\left( \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } \right) \\ \\ =-6\left( \frac{y}{x} \right)=-6\tan\theta$

Therefore, $-6\tan\theta=3\sqrt{7}$ .

Part B:

$- \frac{ \sqrt{7} }{2} =- \frac{ \sqrt{7} }{3} \cdot \frac{3}{ \sqrt{2} } \\ \\ =- \frac{ \frac{ \sqrt{7} }{3} }{ \frac{ \sqrt{2} }{3} } = \frac{ \frac{ \sqrt{7} }{3} }{ -\frac{ \sqrt{2} }{3} } = \frac{y}{x} \\ \\ =\tan\theta$

Therefore, $\tan\theta=- \frac{ \sqrt{7} }{2}$

8 0

3 years ago

-V + 5 + 6V = 1 + 5v + 3

quester [9]

Answer:

Step-by-step explanation:

7 0

3 years ago

"the quotent of a number and 4" i dont wanna fail math

Zielflug [23.3K]

Answer:

N/4

Step-by-step explanation:

quotient is the same as division

since we don't know what the number is we use n as the variable

so n/4

Hope this helps

4 0

2 years ago