3 years ago

Which will result in a difference of squares?

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

Please show the choices

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Are there any values of x or y which are not possible in the function

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2 years ago

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2 years ago

Which expressions are equivalent to g + h + (j + k)? Check all that apply.

Paha777 [63]

Answer:

${ \tt{g + h + (j + k)}} \\ = (g + h) + j + k$

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2 years ago

Read 2 more answers

(GIVING BRAINLIEST AND EXTRA POINTS!!!)

rosijanka [135]

Answer:0.65

Step-by-step explanation:

Firstly, we convert the fractions into decimals:

6/10=0.6

1/5=0.2

1/4=0.25

We then get : 0.6 - 0.2 + 0.25

0.6-0.2=0.4

0.4+0.25=0.65

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2 years ago

Write the equation of the circle with the given center and radius.

34kurt

Step-by-step explanation:

The standard equation of a circle is $(x - h)^2 + (y - k)^2 = r^2$

Center = (h, k)

Center = (0,2)

h = 0

k = 2

r = 5

$(x - h)^2 + (y - k)^2 = r^2$

$(x - 0)^2 + (y - 2)^2 = 5^2$

Center = (-4,-5)

h = -4

k = -5

r = $\sqrt{2}$

$(x - h)^2 + (y - k)^2 = r^2$

$(x - (-4))^2 + (y - (-5))^2 = \sqrt{2}^2$

$(x + 4))^2 + (y + 5))^2 = \sqrt{2}^2$

Center =(-1,3)

h = -1

k = 3

r = 8

$(x - h)^2 + (y - k)^2 = r^2$

$(x - (-1))^2 + (y - 3)^2 = 8^2$

$(x + 1)^2 + (y - 3)^2 = 8^2$

Center: (9,0)

h = 9

k = 0

r = $\sqrt{3}$

$(x - h)^2 + (y - k)^2 = r^2$

$(x - 9)^2 + (y - 0)^2 = \sqrt{3}^2$

4 0

3 years ago