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3 years ago

9

Stacy owes 13.65 for text messging in the month of September if her text messaging plan cost 12 for the first 300 messages and 5

c for each text message how many text messages did she send that month

1 answer:

lara [203]3 years ago

7 0

Answer:

need points

Step-by-step explanation:

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Aldos coffee shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Aldo $4.15 per pound, and type of

bogdanovich [222]

Let A represent amount of Type A coffee pounds used.

Let B represent amount of Type B coffee pounds used

A + B = 156

B = 156 - A

A = 156 - B

5.80A + 4.65B = 826.60

580 (156 - B) + 4.65B - 826.60 = 0

904.8 - 5.80B + 4.65B - 826.60 = 0

904.8 - 1.15B - 826.60 = 0

78.2 - 1.15B = 0

78.2/1.15 = 1.15B/1.15

68 = B

B = 68 pounds of Type B coffee

There's many more steps you can take to check and etc but am too lazy to put down sorry.

3 0

3 years ago

Okay will award brainliest and put alot of points so pls help I'm desparate!!!

Bad White [126]

Answer:

23 is 31/100

Step-by-step explanation:

not sure about the rest sorry :(

7 0

4 years ago

Read 2 more answers

The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class

alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

5 0

3 years ago

What are the solutions to the inequality (x-3)(x+5) SO?

nikitadnepr [17]

Answer:

x

2

+

2

x

−

15

Step-by-step explanation:

3 0

3 years ago

Which piecewise function is shown in the graph?

mash [69]

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function $f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right.$ is shown in the graph attached herein. (Correct choice: A)

<h3>How to determine a piecewise function</h3>

In this question we have a graph formed by two different <em>linear</em> functions. <em>Linear</em> functions are polynomials with grade 1 and which are described by the following formula:

y = m · x + b (1)

Where:

x - Independent variable.
y - Dependent variable.
m - Slope
b - Intercept

By direct observation and by applying (1) we have the following <em>piecewise</em> function:

$f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right.$

Based on the characteristics of <em>linear</em> and <em>piecewise</em> functions, the <em>piecewise</em> function $f(x) = \left \{ {{-0.5\cdot x +1, \,x < 0} \atop {2\cdot x - 2, \,x \ge 0}} \right.$ is shown in the graph attached herein. (Correct choice: A)

To learn more on piecewise functions: brainly.com/question/12561612

#SPJ1

3 0

2 years ago