Basically, you have two circles. You are asked to take circle 1 and "move it" so that it is on top of circle 2. This process of moving is called a translation and can be thought of as sliding. You do this by ensuring that the two have the same center. So, starting at (-4,5) how do you have to move to end up at (2,1)?
To do this we need to move right 6 as the x-coordinate goes from -4 to 2. We also need to move down 4 as the y-coordinate goes from 5 to 1. So we add 6 to the x-coordinate and subtract 4 from the y-coordinate. The transformation rule is (x+6, y-4).
Once you do this the circles have the same center. Next you wish to dilate circle 1 so it ends up being the same size at circle 2. That means you stretch it out in such a way that it keeps its shape. Circle 1 has a radius of 2 centimeters and circle 2 has a radius of 6 centimeters. That is 3x bigger. So we dilate by a factor of 3.
Translations and dilations (along with reflections and rotations) belong to a group known as transformations.
Answer:
- x - 24 = 0
a = 1
b = 1
c = -24
Step-by-step explanation:
(x + 4)(x - 5) = 4
x(x - 5) =
- 5x
4(x - 5) = 4x - 20
- 5x + 4x - 20 = 4
- x - 20 = 4
- x - 20 - 4 = 0
- x - 24 = 0
a = 1
b = 1
c = -24
Answer:
(a) 4 seconds
Step-by-step explanation:
The given point (4, 0) on the parabola tells you the answer to the question: the coin was in the air 4 seconds before its height is 0. It is no longer in the air at that point.
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<em>Additional comment</em>
In order to match the rest of the problem statement, the first given x-intercept must be (-2, 0).
Answer: the answer is A.4
Step-by-step explanation:
Dilation in this context is the transformation is an object into a larger one.
ABC is transformed to A'B'C'
To get the scale factor, we divide the coordinates of A'B'C' by ABC
i.e
A'/A = -28/-7, 32/8 = 4
Or
B'/B = 4/1, -28/-7 = 4
Or
C'/C = 28/7, 24/6 = 4