Question

Sloane kicked a soccer ball at a speed of 48 feet per second. If the ball never leaves the ground, then it can be represented by the function H(t) = −16t2 + 48t. Determine the time the ball traveled. t = 0.33 seconds t = 3 seconds t = 16 seconds t = 48 seconds

Answer 1

Answer:

For t = 0.33 s, H = 14.0976 feet;

For t = 3 s, H = 0 feet;

For t = 16 s, H = -3328 feet;

For t = 48 s, H = -34560 feet.

Step-by-step explanation:

Assuming there's a typo on the problem and it wishes to determine the distance traveled by the ball in the given times instead of the time, we can solve it as shown below:

For t = 0.33 s:

$H(t) = -16*t^2 + 48*t\\H(0.33) = -16*(0.33)^2 + 48*0.33\\H(0.33) = -1.7424 + 15.84\\H(0.33) = 14.0976 \text{ feet}$

For t = 3 s:

$H(t) = -16*t^2 + 48*t\\H(3) = -16*(3)^2 + 48*3\\H(3) = -144 + 144\\H(3) = 0 \text{ feet}$

For t = 16 s:

$H(t) = -16*t^2 + 48*t\\H(16) = -16*(16)^2 + 48*16\\H(16) = -4096 + 768\\H(16) = -3328 \text{ feet}$

For t = 48 s:

$H(t) = -16*t^2 + 48*t\\H(48) = -16*(48)^2 + 48*48\\H(48) = -36864 + 2304\\H(16) = -34560 \text{ feet}$

Answer 2

Answer:

t = 3 seconds

Step-by-step explanation:

I took the test and i got it right.