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Svetlanka [38]
3 years ago
9

1:what is the range of data?

Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

1. b

2. c

3. c

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Subtract using the number line. −4−(8)
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The answer is -12 because the 4 and 8 are negative
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Find the area.<br> 2 ft.<br> 19 ft<br> 4f<br> 5 ft.<br> 7
ch4aika [34]

Answer: 20 ft squared

Step-by-step explanation:

separate the figures

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Suppose you are standing in a parking lot near a building, and the winter air temperature is 0 degrees Celsius. At that temperat
Naily [24]

The building is 231.7 m far away.Distance can refer to a physical length or an estimate based on other factors in physics or common use.

<h3>What is distance?</h3>

Distance is a numerical representation of the space between two objects or locations. |AB| is a symbol for the distance between two points A and B.

Given data;

Speed of sound  = 331 meters per second

Time = 0.7 sec

The distance from the building is;

d=v×t

d=331 m/sec × 0.7 sec

d=231.7 m

Hence the building is 231.7 m far away.

To learn more about the distance refer to the link;

brainly.com/question/26711747

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2 years ago
Solve for x. Round to 3 decimal places
iVinArrow [24]

Answer:

<h2>x = 727</h2>

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\Domain:\ x+2>0\to x>-2\\\\\log_3(x+2)-8=-2\qquad\text{add 8 to both sides}\\\\\log_3(x+2)=6\iff x+2=3^6\\\\x+2=729\qquad\text{subtract 2 from both sides}\\\\x=727\in D

3 0
3 years ago
Read 2 more answers
I need help please I don’t understand
defon

9514 1404 393

Answer:

  1. ∠EDF = 104°

  2. arc FG = 201°

  3. ∠T = 60°

Step-by-step explanation:

There are a couple of angle relationships that are applicable to these problems.

  • the angle where chords meet is half the sum of the measures of the intercepted arcs
  • the angle where secants meet is half the difference of the measures of the intercepted arcs

The first of these applies to the first two problems.

1. ∠EDF = 1/2(arc EF + arc UG)

  ∠EDF = 1/2(147° +61°) = 1/2(208°)

  ∠EDF = 104°

__

2. ∠FHG = 1/2(arc FG + arc ES)

  128° = 1/2(arc FG +55°) . . . substitute given information

  256° = arc FG +55° . . . . . . multiply by 2

  201° = arc FG . . . . . . . . . subtract 55°

__

3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.

  ∠T = 1/2(arc FS -arc US)

  ∠T = 1/2(170° -50°) = 1/2(120°)

  ∠T = 60°

3 0
3 years ago
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