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2 years ago

Can someone please answer my trigonometry problem? I've been trying to get answers all day for something so minimal.

Mathematics

1 answer:

Fantom [35]2 years ago

8 0

Answer:

∠B ≈ 30.0°

Step-by-step explanation:

The law of sines can be used to solve a triangle when two sides and an angle opposite one of them are given.

sin(B)/b = sin(C)/c

sin(B) = (b/c)sin(C) . . . . solve for sin(B)

sin(B) = (14/28)sin(91°) ≈ 0.49992385

The angle is found using the inverse sine function:

B = arcsin(0.49992384) ≈ 29.99496°

Rounded to tenths, the angle is ...

m∠B ≈ 30.0°

_____

<em>Additional comments</em>

Many triangle solver apps and web sites are available if all you want is an answer.

When using your calculator, be sure the angle mode is set to "degrees."

The Law of Sines can also be used to solve a triangle when two angles and one side are known.

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3 years ago

If ΔRED ≅ ΔTAN, then which of the following statements is not true? RE ≅ TA ∠E ≅ ∠A RD≅ TA ∠D ≅ ∠N

Assoli18 [71]

Answer:

RD≅ TA

Step-by-step explanation:

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3 years ago

Which of the following arithmetic sequences have a common difference of ? -4,-1.5,1,3.5,6,8.5 1.5,3,4.5,6,7.5

zavuch27 [327]

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3 years ago

The altitude of a triangle is increasing at a rate of 1 cm/ min while the area of the triangle is increasing at a rate of 2 cm2

serg [7]

Ya, calculus and related rates, such fun!

everything is changing with respect to t

altitude rate will be dh/dt and that is 1cm/min
dh/dt=1cm/min

area will be da/dt which is increasing at 2cm²/min
da/dt=2cm²/min

base=db/dt

alright

area=1/2bh
take dervitivie of both sides
da/dt=1/2((db/dt)(h)+(dh/dt)(b))
solve for db/dt
distribute
da/dt=1/2(db/dt)(h)+1/2(dh/dt)(b)
move
da/dt-1/2(dh/dt)(b)=1/2(db/dt)(h)
times 2 both sides
2da/dt-(dh/dt)(b)=(db/dt)(h)
divide by h
(2da/dt-(dh/dt)(b))/h=db/dt

ok
we know
height=10
area=100
so
a=1/2bh
100=1/2b10
100=5b
20=b

so
h=10
b=20
da/dt=2cm²/min
dh/dt=1cm/min

therefor
(2(2cm²/min)-(1cm/min)(20cm))/10cm=db/dt
(4cm²/min-20cm²/min)/10cm=db/dt
(-16cm²/min)/10cm=db/dt
-1.6cm/min=db/dt

the base is decreasing at 1.6cm/min

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NeTakaya

Answer:

Step-by-step explanation:

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