6 phone numbers are possible for one area code if the first four numbers are 202-1
<u>Solution:</u>
Given that, the first four numbers are 202-1, in that order, and the last three numbers are 1-7-8 in any order
We have to find how many phone numbers are possible for one area code.
The number of way “n” objects can be arranged is given as n!
Then, we have three places which changes, so we can change these 3 places in 3! ways
Hence 3! is found as follows:
So, we have 6 phone numbers possible for one area code.
For f(x)=1/x^2-3
Find
A) f(3)
B) f(2-h)
If f(x)=1/x^2-3, then f(3) = 1 / 3^2 - 3. The exponentiation here must be carried out first: f(3) = 1/9 - 3. Then f(3) = 1/9 - 27/9 = -26/9
If f(x)=1/x^2-3, then f(2-h) = 1 / [2-h]^2 - 3. This result may be left as is or expanded. In expanded form, we have:
1
f(2-h) = ------------------ - 3
4-4h +h^2
Answer:
B
Step-by-step explanation:
The graph is a sine curve but multiplied by -1
Answer:
672 sq cm
Step-by-step explanation:
Each triangular base is 1/2 (12 * 8) or 48, making them = 96.
One of the sides is 12 x 18 = 216
The other 2 sides are 10 x 18 = 180 x 2 = 360
Add them all together to get 672 sq cm
