Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Jenna gets paid a total of 10.97 cents an hour<span />
9514 1404 393
Answer:
6
Step-by-step explanation:
The slope of the line between (3, 3) and (4, 9) is given by the slope formula:
m = <average rate of change> = (y2 -y1)/(x2 -x1)
m = (9 -3)/(4 -3) = 6/1
m = 6
The average rate of change on the interval [3, 4] is 6.
Answer:
4
Step-by-step explanation:
4 is the answer
Answer:
The answer is C; (5, 1).
Step-by-step explanation:
2(5) - 1 = 9
10 - 1 = 9
9 = 9
9 = 9 is a true statement so the answer is C.
