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love history [14]
3 years ago
6

Can someone please graph this and tell me what the slope is??

Mathematics
1 answer:
Ratling [72]3 years ago
3 0
7 is slope I am sure so go ahead and be happy

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Find the surface area of the pyramid *the side lengths are equal*❤️
Vera_Pavlovna [14]
I think you times them
4 0
3 years ago
the parent function of the function g(x)=(x-h)^2+k is f(x)=x^2. the vertex of the function g(x) is located at (9,8). what are th
Lunna [17]

Answer:

<h2>h = 9, k = 8</h2>

Step-by-step explanation:

\text{The vertex form of an an equation of a quadratic function:}\\\\y=a(x-h)^2+k\\\\(h,\ k)-vertex\\\\\text{We have}\ g(x)=(x-h)^2+k,\ \text{and the vertex in}\ (9,\ 8).\\\\\text{Therefore}\ h=9\ \text{and}\ k=8.\ \text{substitute:}\\\\g(x)=(x-9)^2+8

8 0
3 years ago
What is the slope of the line tangent to the curve y+2 = (x^2/2) - 2siny at the point (2,0)?
kirza4 [7]
<span>, y+2 = (x^2/2) - 2sin(y) so we are taking the derivative y in respect to x so we have dy/dx use chain rule on y so y' = 2x/2 - 2cos(y)*y'

</span><span>Now rearrange it to solve for y' y' = 2x/2 - 2cos(y)*y' 0 = x - 2cos(y)y' - y' - x = 2cos(y)y' - y' -x = y'(2cos(y) - 1) -x/(2cos(y) - 1) = y'
</span><span>we know when f(2) = 0 so thus y = 0 so when f'(2) = -2/(2cos(0)-1)
</span><span>2/2 = 1
</span><span>f'(2) = -2/(2cos(0)-1) cos(0) = 1 thus f'(2) = -2/(2(1)-1) = -2/-1 = 2 f'(2) = 2
</span>
6 0
3 years ago
Read 2 more answers
Given that<br> x:8=2:x<br> Calculate the positive value of x.
kow [346]

Answer:

x = 4

Step-by-step explanation:

x : 8 = 2 : x \\  \frac{x}{8}  =  \frac{2}{x}  \\  \\ cross \:  \: multiple \\  {x}^{2}  = 16 \\ x =  \sqrt{16}  \\ x = 4

4 0
3 years ago
Read 2 more answers
Is the given pair a solution <br>y=-x -2; (2,-4)
nignag [31]
Yes
because
when x =2 then y = -(2) - 2 = -4

so (2,-4) is a solution

hope it helps
6 0
3 years ago
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