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melamori03 [73]
3 years ago
14

An 8-ounce box of Crispy Crackers costs $1.59 and a 32-ounce box costs $6.79. Which box is the better buy?

Mathematics
2 answers:
kozerog [31]3 years ago
8 0

Answer:

A.

8 oz for 0.20/oz

Step-by-step explanation:

1.59 divided by 8 is =0.198

That rounds to 0.20.

The cost of an 8-ounce box of Crispy Crackers is 0.20/oz.

32 divided by 6.79 = 4.71

The cost of a 32-ounce box cost is 4.71/oz

0.20 < 4.71

mash [69]3 years ago
6 0
Answer:
A. !!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Please answer ASAP. Due in 5 minutes!!
Goryan [66]

Answer:

Step-by-step explanation:

2 feet 8 inches = 32 inches

4 yards = 144 inches

9 feet = 3 yards

2 yards and 5 inches= 77 inches

7 0
3 years ago
What’s the answer pleazzzzz helplllllll 9m^2-4m-6 by 3m
dlinn [17]

Answer

D. 3m - 4/3 -2/m


<u>Explanation</u>

(9m²-4m-6) ÷ 3m  = 9m²/3m - 4m/3m - 6/3m

Carry out the division, each term is divided by 3m.

9m²/3m = 3m

- 4m/3m = -4/3

- 6/3m = - 2/m

Finally you will get,

<em>3m - 4/3 -2/m</em>

5 0
3 years ago
Describe the locus that the figure represents.
Harlamova29_29 [7]
The correct answer is: <span>all points equidistant from point A and point B

Explanation:

If you draw lines from Point A to the line and and from Point B to the line (perpendicular to the line), you would see that the distances from both these points to the line would be the same. Likewise if apply the symmetry argument on both of the points, you would find out that all points on the line would be equidistant from point A and point B. Hence Option (B) is correct.</span>
7 0
3 years ago
A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the
LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1

The probability that at most 12 ties are too tight is P=1.

5 0
3 years ago
What are the solutions to the equation y2-1=35
Tanya [424]

y^2-1= 35

Move -1 to the other side. Sign changes from -1 to +1.

y^2-1+1= 35+1

y^2= 36

Square root 36:

6 and -6

Answer: 6 and -6

6 0
3 years ago
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