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3 years ago

What is 6s- 3/4? HELPP

Mathematics

1 answer:

Dmitry [639]3 years ago

8 0

Is that the full question? I can't solve it if s is a variable

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Which of the following are solutions to the equation 2cos2x-1=0

loris [4]

Answer:

x = π/4 and 5π/4

Step-by-step explanation:

Given the expression;

2cos²x - 1 = 0

2cos²x = 0+1

2cos²x = 1

cos²x = 1/2

cos x = ±√1/2

cos x = ±0.7071

x = arccos(±0.7071)

x = ±45 degrees

Convert to radians

Sence 180° = π rad

45° = x

x = 45π/180

x = π/4

If x = -45°

Since cos is negative in the 3rd quadrant

x = 180 + 45

x = 225°

x = 225π/180

x = 45π/36

x = 5π/4

8 0

2 years ago

The school has t-shirts to hand out. They have 10 hot pink shirts, 6 neon green shirts, 9 bright yellow shirts, and 11 vibrant b

Alex17521 [72]

Answer:

A. 11/36

Step-by-step explanation:

Add all the numbers together(36), and then see how many out of that number are the vibrant blue shirt. Since they are asking the probability of you being given a vibrant blue shirt, and there are 11 out of the 36 shirts, therefore you have an 11/36 chance that you will be given a vibrant blue shirt.

5 0

3 years ago

Read 2 more answers

What is 36,100 dived by 36,789

Stolb23 [73]

36100/36789=0.9812715757427492

3 0

3 years ago

Read 2 more answers

Tyler ate x fruit snacks, and Han ateless than that. Write an equation to represent the relationship between the number Tyler at

irga5000 [103]

Answer:

x < y

Step-by-step explanation:

4 0

2 years ago

Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-

Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

$\sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0

3 years ago