Answer:
-21
Step-by-step explanation:
-21 x 2 = -42 -42+16= -26
Answer:

Step-by-step explanation:
Given
Points: (1, 9) and (9, 3)
Ratio = 2/3
Required
Determine the coordinate of the center
Represent the ratio as ratio

The new coordinate can be calculated using

Where



Substitute these values in the equation above



Hence;
<em>The coordinates of the new center is </em>
<em></em>
<u>The given options are:</u>
(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
(B)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector.
(C)the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector.
(D)the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.
Answer:
(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.
Step-by-step explanation:
The area of the shaded sector can be determined using the formula:



Therefore, the formula is:

Therefore, the formula is best explained by Option A.
The maximum compression of the spring is 0.276 m
Step-by-step explanation:
First of all, we calculate the spring constant of the spring, by using Hooke's law:

where
F = 10 kN = 10,000 N is the force applied
x = 1.25 cm = 0.0125 m is the corresponding compression of the spring
k is the spring constant
Solving for k,

When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write
(1)
where
m is the mass of the truck
v = 2 m/s is the initial speed of the truck
is the spring constant
x is the compression of the spring
The mass of the truck can be found from its weight:

So now we can re-arrange eq.(1) to find the compression, x:

Learn more about kinetic energy:
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