Multiplying complex numbers is a lot like multiplying binomial terms. The only relation one has to remember when dealing with complex numbers is that i² = -1.

Now let us try to multiply binomials. This is done by adding the products of the first term of the first binomial distributed to the second binomial, and the second term of the first binomial distributed to the second binomial. This is done below:

(3 – 5i)(–2 + 4i) = -6 + 12i + 10i -20i²

Simplifying and applying i² = -1:
-6 + 22i - 20(-1)
-6 + 22i + 20
14 + 22i

Among the choices, the correct answer is B.

5 0

3 years ago

Read 2 more answers

What theorem is this sss,sas,asa,aas,hl, or not enough info

svp [43]

ASA - verticals angles are equal, two sides are equal, and two other angles are marked equal

6 0

3 years ago

3 and 1/3 minus 2 and 5/6

Rama09 [41]

$3\dfrac{1}{3}-2\dfrac{5}{6}$

Find the common denominator

LCM(3, 6) = 6

$3\dfrac{1}{3}=3\dfrac{1\cdot2}{3\cdot2}=\3\dfrac{2}{6}\\\\3\dfrac{1}{3}-2\dfrac{5}{6}=3\dfrac{2}{6}-2\dfrac{5}{6}=2\dfrac{6+2}{6}-2\dfrac{5}{6}=2\dfrac{8}{6}-2\dfrac{5}{6}=(2-2)+\left(\dfrac{8}{6}-\dfrac{5}{6}\right)\\\\=\dfrac{8-5}{6}=\dfrac{3}{6}=\dfrac{3:3}{6:3}=\boxed{\dfrac{1}{2}}$

7 0

3 years ago