Answer:
NUMBER 1.)
Step 1
Subtract 3y3y from both sides.
5x=10-3y5x=10−3y
Step 2
Divide both sides by 55.
\frac{5x}{5}=\frac{10-3y}{5}
5
5x
=
5
10−3y
Hint
Undo multiplication by dividing both sides by one factor.
Step 3
Dividing by 55 undoes the multiplication by 55.
x=\frac{10-3y}{5}x=
5
10−3y
Hint
Undo multiplication.
Step 4
Divide 10-3y10−3y by 55.
x=-\frac{3y}{5}+2x=−
5
3y
+2
Hint
Divide.
Solution
x=-\frac{3y}{5}+2x=−5
3y+2
Step-by-step explanation:
NUMBER 2.)
Step 1
Add 4y4y to both sides.
3x=6+4y3x=6+4y
Step 2
The equation is in standard form.
3x=4y+63x=4y+6
Step 3
Divide both sides by 33.
\frac{3x}{3}=\frac{4y+6}{3}
3
3x
=
3
4y+6
Hint
Undo multiplication by dividing both sides by one factor.
Step 4
Dividing by 33 undoes the multiplication by 33.
x=\frac{4y+6}{3}x=
3
4y+6
Hint
Undo multiplication.
Step 5
Divide 6+4y6+4y by 33.
x=\frac{4y}{3}+2x=
3
4y
+2
Hint
Divide.
Solution
x=\frac{4y}{3}+2x= 3
4y+2
Answer:
E
Step-by-step explanation:
So first, you have to get two of the same variables to cancel out. Let's do this for x. In order for the x's to cancel out, we could multiply the bottom problem by 2.
(2) 3x-6y=24
After multiplying all the numbers by 2, you get the equation 6x-12y=48
The set of equations is now
-6x+2y=12
6x-12y=48
Now you can add them. The x variables cancel out, so you are left with the y variable.
2y+-12y=-10y and 12+48=60
Then you would divide 60 by -10 to get y=-6.
You would plug the answer for y into one of the original equations, lets do the top one. -6x+2y=12 becomes -6x+2(-6)=12
You'd multiply the 2 and -6 to get -12 so the equation is
-6x-12=12
The negative 12 turn positive and you add to both sides to get the -6x alone.
-6x-12=12
+12=12
-6x=24
Then divide 24 by -6
X=4
(-4,-6) is your final answer.
Since you know that DA and DC are equal in length, you can say 2x-3=x+2, when you add 3 to both sides, it becomes 2x=x+5, subtract x from both sides, and you find that x=5
