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alexandr402 [8]
3 years ago
9

In circle L with KNM= 53, find the angle measure of minor arc KM

Mathematics
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

106

Step-by-step explanation:

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Simplify to create an equivalent expression 19−6(−k−2)
Nikolay [14]
<span>19 − 6( − k − 2) 

Distribute -6:
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Combine like terms:
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Answer: </span>6k + 31
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Answer:

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Step-by-step explanation:

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The state of Vermont can be modeled by a quadrilateral like the one shown. Which is the perimeter of the quadrilateral?
Sveta_85 [38]

Answer:

440 miles

Step-by-step explanation:

Perimeter of a quadrilateral, P :

P = a + b + c + d

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3 years ago
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svp [43]

The way that I memorised how to do sin, cos, and tan is by the following: SOH, CAH, TOA

SOH = Sin is OPPOSITE / HYPOTENUSE

CAH = Cos is ADJACENT / HYPOTENUSE

TOA = Tan is OPPOSITE / ADJACENT

For example if we were to solve question 5

Sin T = 6 root 2 / 19

Cos T = 17 / 19

Tan T = 6 root 2 / 17

Repeat the steps for question 6

For the rest of the questions (7,8,9) you have to take the information given and figure out if you should us Sin, cos, or Tan. then plug the numbers in the calculator and while doing sin ^ -1, cos ^ -1, tan ^ -1

for example on question 7, to find the angle x they have given you the hypotenuse and the adjacent side so

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8 0
2 years ago
Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th
Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0

5 0
3 years ago
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