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Shalnov [3]
3 years ago
6

What must the radius of C be for PR to be tangent to it at Q?

Mathematics
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

D. 8

Step-by-step explanation:

Draw segment CQ which will be perpendicular to tangent PR.

So, triangle CQR will be right angled triangle right angle at Q.

Let radius of the circle be r.

Therefore,

CQ = CS = r

By Pythagoras Theorem:

{(r + 9)}^{2}  =  {r}^{2}  +  {15}^{2}  \\  \\  {r}^{2}  + 18r + 81 =  {r}^{2}  + 225 \\  \\ 18r = 225 - 81 \\  \\ 18r = 144 \\  \\ r =  \frac{144}{18}  \\  \\ r = 8

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liraira [26]

Answer:

The answer in decimal form, is;

x= 2.12156883...

The exact form is in the picture below

8 0
2 years ago
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One of the legs of a right triangle measures 6 cm and its hypotenuse measures 10 cm. Find the measure of the other leg. If neces
Liula [17]

Answer:

let base = 6cm

perpendicular =x cm

hypotenuse =10cm

by using Pythagoras law

hypotenuse ²=perpendicular ²+base²

10²=x²+6²

100-36=x²

x=√64=8cm

the measure of the other leg is 8cm

6 0
3 years ago
Solve for y, z, x or t:
Andrews [41]

Problem 1

y + (y/a) = b

a*( y + (y/a) ) = a*b ... multiply both sides by 'a'

ay + a(y/a) = ab ... distribute

ay + y = ab

(a+1)y = ab .... factor

y(a+1) = ab

y = ab/(a+1) ... divide both sides by (a+1)

<h3>Answer: y = ab/(a+1)</h3>

========================================

Problem 2

z - a = z/b

b(z - a) = b(z/b) .... multiply both sides by b

b(z - a) = z

bz - ab = z ... distribute

bz - ab+ab = z+ab ... add ab to both sides

bz = z+ab

bz-z = z+ab-z ... subtract z from both sides

bz-z = ab

z(b-1) = ab .... factor

z = ab/(b-1) .... divide both sides by (b-1)

<h3>Answer: z = ab/(b-1) </h3>

========================================

Notes:

To clear out the fractions, I multiplied both sides by the denominator value.

The restriction that 'a' cannot equal -1, back in problem 1, is to avoid having the denominator (a+1) be equal to zero. We cannot divide by zero. A similar situation happens with problem 2 as well.

4 0
3 years ago
PLZ HELP
SCORPION-xisa [38]

Answer:

(y + 14)(y - 14)

Step-by-step explanation:

A difference of squares has the general form

a³ - b² and factors as

(a + b)(a - b)

Given

y² - 196

y² = (y)² ⇒ a = y and 196 = 14² ⇒ b = 14

y² - 196

= y² - 14² = (y + 14)(y - 14) ← difference of squares

8 0
3 years ago
Javier volunteers in community events each month. He does not do more than five events in a month. He attends exactly five event
mezya [45]

Answer:

The probability of Javier volunteers for less than three a month is 25%

Step-by-step explanation:

According to the questions,

The probability of Javier to attend exactly 5 events :-

P ( x = 5 ) = 25% = \frac{1}{4}

The probability of Javier to attend exactly 4 events :-

P ( x = 4 ) = \frac{1}{4}

The probability of Javier to attend exactly 3 events :-

P ( x = 3 ) = \frac{1}{4}

The probability of Javier to attend exactly 2 events :-

P ( x = 2 ) = \frac{3}{20}

The probability of Javier to attend exactly 1 events :-

P ( x = 1 ) = \frac{1}{20}

The probability of Javier to attend no events :-

P ( x = 0 ) = \frac{1}{20}

Now we have to calculate the probability of Javier volunteers for less than three P ( x < 3 ).

P ( x < 3 ) = P ( x = 0 ) + P ( x = 1 ) + P ( x = 2 )

P ( x < 3 ) = \frac{1}{20} + \frac{1}{20} + \frac{3}{20}   = \frac{1 + 1 + 3}{20}  = \frac{5}{20}  = \frac{1}{4}   = 0.25 = 25 %.

8 0
3 years ago
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