Step-by-step explanation:
Given that,
The quadratic equation that models the ball's height above the ground h, t seconds after it was thrown is given by :
...(1)
(a) For maximum height, put dh/dt = 0
So,

Put the value of t in equation (1).
So,

(b) When the ball reaches the ground,
h = 0
So,

So, the ball hits the ground in 7 seconds.
2
-4(2)^-2 + 3(5)^0
-4/2^2+3
-1+3
2
the x^-2 moves to the denominator
anything to the 0 power is 1
Answer:
AB = 14 units
∠F = 39°
Step-by-step explanation:
Given:
ΔABC ≅ ΔDEF
So,
AB = ED (By CPCT)
So,
AB = 14 units
∠C = ∠F (By CPCT)
∠F = 39°