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2 years ago

HELP PLEASE ANSWER NOW

Mathematics

2 answers:

lbvjy [14]2 years ago

3 0

Answer:

(7,2)

Step-by-step explanation:

Multiply the first equation by -3

(x-3y=1) = -3x+9y=-3

Combine like terms with the new equation and the second equation

(-3x+9y=-3) + (3x-5y=11) = 4y=8

Divide each side by 4

4y/4=8/4

y=2

Plug in 2 for y in any equation. It doesn’t matter which one

x-3(2)=1

Distribute

x-6=1

Add 6 to both sides

x-6=1

+6 +6

x=7

sveta [45]2 years ago

3 0

Answer: x = 7 y = 2

(7, 2)

Step-by-step explanation:

Multiply the first equation by -3 and the second by 1:

-3(x - 3y = 1)

1(3x - 5y = 11)

Becomes:

-3x + 9y = -3

3x - 5y = 11

Add the equations to eliminate x:

-3x + 9y = -3

3x - 5y = 11

4y = 8

Solve for y by dividing by 4:

4y/4 = 8/4

y = 2

Now we plug in y to the first equation:

x - 3 ( 2 ) = 1

x - 6 = 1

Add 6 to both sides:

x - 6 + 6 = 1 + 6

x = 7

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Sphinxa [80]

Answer: 2/3 (two thirds)

Explanation: Divide both denominator and numerator by the common factor of fourteen

3 0

2 years ago

Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec

expeople1 [14]

Answer:

$cot x = \frac{cos x}{sin x}$

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

$cos x cot x + sin x$

We know from math properties that the definition for cot is $cot x = \frac{cos x}{sin x}$

If we use this definition we got:

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

Now we can use the following identity:

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

4 0

3 years ago

Find the sum of 12a + 7b, −6a − 9, and 14a − 12b.

Ivan

The answer is: [A]: " 20a − 5b − 9 " .
______________________________________
Explanation:
_______________________________________________
(12a + 7b) + (−6a − 9) + (14a − 12b) =

12a + 7b + 1(−6a − 9) + 1(14a − 12b) =

12a + 7b + (1*-6a) + (1*-9) + (1*14a) + (1* -12b) =

12a + 7b − 6a − 9 + 14a − 12b = ?

Combine the "like terms:

12a − 6a + 14a = 20a ;

7b − 12b = - 5b ;

and then we have "-9" ;
_____________________________________________________
So, write as: " 20a − 5b − 9 " ; which is: Answer choice: [A].
______________________________________________________

8 0

2 years ago

Read 2 more answers

For this question I am sure the answer is 81% as you divide 45 and 55. However, it is stating my answer is incorrect even though

77julia77 [94]

Answer:

it says round to the nearest 10th so it wouldn't be 81, it would be 81.8%

8 0

2 years ago

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aev [14]

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