Answer:
11/7 feet
Step-by-step explanation:
the perimeter of a circle is πr²
and a semi circle is half of a circle then the formula would be 1/2 πr²
1/2×22/7×1 (it is 1 because we have divided the diameter to get radius
so we derived at 11/7
Answer:
327 children and 318 adults
Step-by-step explanation:
The x be the amount of children and y be the amount of adults that were at the swimming pool. We can use this to set up a system of equations:
x+y=645
1.75x+2.50y=1367.25
Move y to the other side in the first equation to isolate x and solve the system using substitution:
x=645-y
1.75(645-y)+2.50y=1367.25
Distribute
1128.75-1.75y+2.50y=1367.25
1128.75+0.75y=1367.25
Subtract 1128.75 from both sides
0.75y=238.5
Divide both sides by 0.75
y=318
x=645-y
x=645-318
x=327
327 children and 318 adults swam at the pool that day
Answer:
x = ±2√5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Multiple Roots
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
4x² - 5 = 75
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Addition Property of Equality] Add 5 on both sides: 4x² = 80
- [Division Property of Equality] Divide 4 on both sides: x² = 20
- [Equality Property] Square root both sides: x = ±2√5
Answer:
Kindly check explanation
Step-by-step explanation:
The hypothesis :
H0 : μ1 = μ2
H1 : μ1 > μ2
Given :
x1 = 21.1 ; n1 = 53 ; s1 = 1.1
x2 = 20.7 ; n2 = 46 ; s2 = 1.2
The test statistic :
(x1 - x2) / √[(s1²/n1 + s2²/n2)]
(21.1 - 20.7) / √[(1.1²/53 + 1.2²/46)]
0.4 / 0.2326682
Test statistic = 1.719
The degree of freedom using the conservative method :
Comparing :
Degree of freedom = n - 1
Degree of freedom 1 = 53 - 1 = 52
Degree of freedom 2 = 46 - 1 = 45
Smaller degree of freedom is chosen ;
The Pvalue from Test statistic, using df = 45
Pvalue = 0.0462
Pvalue < α ; Hence, there is significant evidence to conclude that average age of Gorka student is higher than Yaphoa.
