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shutvik [7]
3 years ago
7

Find the volume of the figure.

Mathematics
2 answers:
Yakvenalex [24]3 years ago
8 0

Answer:

233 in^3

Step-by-step explanation:

First we will find the volume of the square at the bottom

V = s^3  where s is the side length

V = 5^3

V = 125 in^3

Then we will find the volume of the rectangular prism at the top

V = l*w*h

V = 12*3*3

V =108 in^3

The total volume is the sum of the two volumes

V = 125+108

    = 233 in^3

Olegator [25]3 years ago
5 0

Answer:

233 in³

Step-by-step explanation:

Cube + cuboid

(5×5×5) + (3×3×12)

233 in³

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Answer:

= -8

(hope this helps) :)

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3 years ago
A classmate said that AB &amp; DC are complementary and parallel based on the diagram below. Explain your classmate's error. Not
Ugo [173]

Your classmate's error about AB and DC being complimentary and parallel is that they misapplied the alternate angle property.

<h3>Why are AB and DC not parallel?</h3><h3 />

There isn't enough evidence presented in the diagram to say that AB and DC are parallel.

The evidence required would be proof that angle AWZ is equal to angle WZY.

Instead, all we have is that  angle AWZ and angle XYC are equal which does not tell us what we need to know about AB and DC being parallel.

Find out more on properties of parallel lines at brainly.com/question/24607467

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3 0
11 months ago
A tennis player gets an ace on 35% of his serves. Out of 80 serves about how many aces will he get
kari74 [83]

Answer:

28

Step-by-step explanation:

His aces on 80 serve = 35% of 80

= 35/100 × 80

= 28

7 0
3 years ago
Read 2 more answers
Find the equation of the line that passes through (-12, 3) and (6, -9). Write your answer in simplified slope-intercept form.
Travka [436]

Answer:

y=-2/3x-5

Step-by-step explanation:

3 0
3 years ago
Determine whether the following are subspaces of R2×2 : (a) Thesetofall2×2diagonalmatrices (b) The set of all 2 × 2 triangular m
Mrrafil [7]

A vector space V is a subspace of a vector space W if

  • V is non-empty,
  • for any two vectors v_1,v_2\inV we have v_1+v_2\in V, and
  • for any scalar k and v\in V we have kv\in V.

It's easy to show the first condition is met by all the sets in parts (a-g).

(a) is a subspace of \Bbb R^{2\times2} because adding any 2x2 diagonal matrices together, or multiplying one by some scalar, gives another diagonal matrix.

(b) and (c) are also subspaces for the same reasons.

(d) is not a subspace because \Bbb R^{2\times2} because this set of matrices does not contain the zero matrix.

(e), however, is a subspace. Any linear combination of matrices in this set always yields a matrix with 0 in row 1, column 1 entry.

(f) is a subspace. A symmetric matrix is one of the form

\begin{bmatrix}a&b\\b&c\end{bmatrix}

Adding two symmetric matrices gives another symmetric matrix:

\begin{bmatrix}a_1&b_1\\b_1&c_1\end{bmatrix}+\begin{bmatrix}a_2&b_2\\b_2&c_2\end{bmatrix}=\begin{bmatrix}a_1+a_2&b_1+b_2\\b_1+b_2&c_1+c_2\end{bmatrix}

(g) is not a subspace. Consider the matrices

\begin{bmatrix}1&0\\0&0\end{bmatrix},\begin{bmatrix}0&0\\0&1\end{bmatrix}

Both matrices have determinant 0, but their sum is the identity matrix with determinant 1.

4 0
3 years ago
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