Answer:
international network is the answer
mbly code to implement the y=(x1+x2)*(x3+x4) expression on 2-address machine, and then display the value of y on the screen. Assume that the values of the variables are known. Hence, do not worry about their values in your code.
The assembly instructions that are available in this machine are the following:
Load b, a Load the value of a to b
Add b, a Add the value of a to the value of b and pla
Answer:
# Solve the quadratic equation ax**2 + bx + c = 0
# import complex math module
import cmath
a = 1
b = 5
c = 6
# calculate the discriminant
d = (b**2) - (4*a*c)
# find two solutions
sol1 = (-b-cmath.sqrt(d))/(2*a)
sol2 = (-b+cmath.sqrt(d))/(2*a)
print('The solution are {0} and {1}'.format(sol1,sol2))
Hope This Helps!!!
Answer:
#include <iostream>
using namespace std;
int cube(int num)//function cube..
{
return num*num*num;
}
int main() {
int result=cube(4);//result stores the value of cube(4).
cout<<result;//displaying it to the screen.
return 0;
}
Explanation:
The above code is in C++ language.The function cube is passed with value 4 and the result of it is stored in the variable result of integer type.Then the result is displayed using the cout. Which is used to print the statement to the output screen.
