Answer: 0.87400mg of caffeine.
Step-by-step explanation:
You have
N(t)=N0(e^−rt)(1)
as a general Exponential decay equation where N0 is the amount at t=0, N(t) is the amount remaining at time t and r is the exponential decay constant. You're specifically given that after 10 hours, the decay factor is 0.2601, i.e.,
N(10)/N(0)=N0(e^−10r)/N0(e^0)= e^−10r=0.2601 . .(2)
Taking the last 2 parts of (2) to the power of 0.1t gives
e^−rt=0.2601^.1t . .(3)
This means that
N(t)=N0(e^−rt)=N0(0.2601^.1t). .(4)
Also,
N(2.56)N(1.56)=N0(0.2601.1(2.56))N0(0.2601.1(1.56))=0.2601.1(2.56−1.56)=0.2601^.1
= 0.87400mg of caffeine.
Yes (I guess)
(-1, 2) Lies on a line so im guessing it is...
Answer:
Subtract
1
1
1
from both sides of the equation
2
+
1
=
1
1
2
+
1
−
1
=
1
1
−
1
2
Simplify
3
Divide both sides of the equation by the same term
4
Simplify
Solution
=
5
Step-by-step explanation:
Answer:
<h2>x= -3</h2>
Step-by-step explanation:
