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ziro4ka [17]
3 years ago
7

Help pls need answer

Mathematics
1 answer:
blagie [28]3 years ago
4 0

Answer:

a

Step-by-step explanation:

idk

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The measure of an exterior angle of a triangle is 3x-5 degrees. The measure of the corresponding interior angle is 5x+17 degrees
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Things to remember the sum of the measures of the interior and exterior angles at each vertex is 180 (supplementary angles) add and equal to 180 3x-5+5x+17= 180 8x+12=180 8x= 168 x=21 substitute in the algebraic expression for exterior angle 3(21) -5= 63-5=58 58 degrees is the exterior angle hope this helps
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A line passes through the points (0, 2) and (1, 6). What is its equation in slope-intercept form?
olchik [2.2K]

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y=4x+2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-2)/(1-0)

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y-2=4(x-0)

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4 0
3 years ago
Which of the following is the product of the rational expressions shown below? 7x/x-4•x/x+7
Gre4nikov [31]
<h2>The product of the rational expressions\dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}.</h2>

Step-by-step explanation:

We have,

\dfrac{7x}{x-4}.\dfrac{x}{x+7}

To find, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = ?

∴ \dfrac{7x}{x-4}.\dfrac{x}{x+7}

= \dfrac{7x.x}{(x-4)(x+7)}

= \dfrac{7x^2}{(x(x+7)-4(x+7)}

= \dfrac{7x^2}{x^2+7x-4x-28}

= \dfrac{7x^2}{x^2+3x-28}

Thus, the product of the rational expressions \dfrac{7x}{x-4}.\dfrac{x}{x+7} = \dfrac{7x^2}{x^2+3x-28}.

7 0
3 years ago
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