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3 years ago

Help pls need answer

Mathematics

1 answer:

blagie [28]3 years ago

4 0

Answer:

Step-by-step explanation:

idk

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(3) The difference between two numbers is 8. If the larger is

Alecsey [184]

Answer:

x= 62

y= 54

Step-by-step explanation:

Step one:

given data

let the numbers be x and y and the larger be x the smaller be y

The difference between two numbers is 8

x-y= 8-----------1

If the larger is subtracted from three times the smaller, the difference is 100

3y-x=100------------2

from eqn 1, x= 8+y

put this in eqn 2

3y-(8+y)=100

3y-8-y=100

collect liker terms

3y-y-8=100

2y=108

y= 54

put y= 54 in eqn 1

x-y=8

x-54= 8

x= 8+54

x=62

5 0

3 years ago

A rectangular yard has dimensions 10 meters by 8 meters. In the middle of the yard is a rectangular pond of 8 square meters, lea

Nikolay [14]

hahahaha i had this same question in my grade

8 0

3 years ago

If they work together, Mark and Yvonne can sort 50 library books in 1.5 hours. Working alone, it would take

Soloha48 [4]

Answer:

Step-by-step explanation:

3 0

3 years ago

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(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi

Drupady [299]

Answer:

a. $\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. $x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. $c = \dfrac{3}{8} \ g/L$

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx = (5·c - 5·c/3)×dt = 20/3·c = $6\frac{2}{3} \cdot c \cdot dt$

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

b. The amount of salt, x after t minutes is given by the relation

$\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c$

$dx = 6\frac{2}{3} \cdot c \cdot dt$

$x(t) = \int\limits \, dx = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt$

$x(t) = 6\frac{2}{3} \cdot c \cdot t$

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

$x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10$

$6\frac{2}{3} \times c =\dfrac{25 \ grams }{10}$

$c =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} } = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200} \ g/L = \dfrac{3}{8} \ g/L$

$c = \dfrac{3}{8} \ g/L$

4 0

3 years ago

WILL MARK BRAINLEIST!! name all segments skew to bc

nordsb [41]

Answer ==== GF, HI, FA, DI

Step-by-step explanation

As long as they aren't on the same plane or aren't touching your given segment, they are skew.

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3 years ago

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