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NeTakaya
3 years ago
9

the initial term of arithmetic sequence is 5. The eleventh term is 125. what is the common difference of the arithmetic sequence

? help meee
Mathematics
1 answer:
kap26 [50]3 years ago
4 0
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
-
f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.



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Answer:

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Step-by-step explanation:

2(3x-4)=5x+6

first get rid of the parentheses by multiplying the  2

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put like terms on one side of the equation. Start with the 5x, move it to the left side

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Again, put like terms on one side of the equation. Move the 8 to the right side

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B)

4x - 3 = 2(x-1)

Start again by getting rid of the parentheses to make it a clean equation... aka distribute the 2:

4x-3 = 2x - 2

Move the like terms to one side of the equation. Start with x.. move 2x to the left:

(4x-3)-2x = (2x-2)-2x

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Move the like terms to one side of the equation.Now move the -3 to the other side:

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3 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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