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Blizzard [7]
3 years ago
14

Use the scale factor 1:25 to find the missing dimension. Item Model Actual Great White Shark Length: ___ cm Length: 8 m

Mathematics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

5cm

Step-by-step explanation:

it the correct answer

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For the function f(x)=5x^3-6, find f^-1
max2010maxim [7]

Answer:

f^{-1} means the inverse function

f^{-1} = \sqrt[3]{(x + 6)/5}

Step-by-step explanation:

f^{-1} means the inverse function

to find an inverse function, flip the x and y variables and solve for y

f(x) = 5x^3 - 6

y = 5x^3 - 6

x = 5y^3 - 6

x + 6 = 5y^3

(x + 6)/5 = y^3

\sqrt[3]{(x + 6)/5} = y

5 0
3 years ago
Which operation would you do second in the following problem?
eimsori [14]

it's addition i looked it up

7 0
3 years ago
Read 2 more answers
Credit card A is running a promotion where they will charge 0% interest for the first year, and then 0.8% interest compounded co
motikmotik

Answer:

Since the total amount you have to pay for the purchase on the credit card A is lower, then it's the best option.

Step-by-step explanation:

For credit card A the ammount will only be compounded after 1 year, so the total time elapsed for the laon is 1.5 years, while for the credit card B it'll be the full 2.5 years. To compute the total amount of a interest compounded continuously we must apply the formula:

M = C*e^(r*t)

Where M is the total amount, C is the initial amount, r is the interest rate and t is the time elapsed.

For credit card A:

M = 500*e^(0.008*1.5) = 506.03614

For credit card B:

M = 500*e^(0.007*2.5) = 508.8270

Since the total amount you have to pay for the purchase on the credit card A is lower, then it's the best option.

7 0
3 years ago
Read 2 more answers
What is the range of y = tan(x) 2?
makkiz [27]
The range of <span><span><span><span><span><span><span>ta</span>n</span>g</span>e</span>n</span>t</span><span><span><span><span><span><span>t⁢a</span>⁢n</span>⁢g</span>⁢e</span>⁢n</span>⁢t</span></span> is all real numbers.
<span><span>
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7 0
3 years ago
How to solve for first derivative?? I have two questions, one where I have the answer, however one where I don’t. The format of
rjkz [21]

Answer:

Q1: f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

Q2: f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

Step-by-step explanation:

The derivative of the product of two functions is:

f(x) = v(x)u(x)

f'(x) = v(x)u'(x) + u(x)v'x)

The derivative is the product of the first function and the derivative of the second function added to the product of the second function and the derivative of the first function.

Q1: The function you are given is:

f(x) = 6x^8(-6x^8 + 2x^4 + 4)

You can think of that function as the product of functions

u(x) = 6x^8 and v(x) = -6x^8 + 2x^4 + 4

We first find the derivatives of functions u and v:

u'(x) = 48x^7 and v'(x) = -48x^7 + 8x^3

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^8)(-48x^7 + 8x^3) + (-6x^8 + 2x^4 + 4)(48x^7)

Use the commutative property to change the order of the sum.

f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

This is the solution you have.

Q2: The function you are given is:

f(x) = 6x^4(6x^3 - 6x^9 + 3)

You can think of that function as the product of functions

u(x) = 6x^4 and v(x) = 6x^3 - 6x^9 + 3

We first find the derivatives of functions u and v:

u'(x) = 24x^3 and v'(x) = 18x^2 - 54x^8

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

5 0
3 years ago
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