3. The table shows the number of hours that a grouped of students spent studying for the SAT during their first week of preparat
ion. The students each add 4 hours to their study times in the second week. What are the mean, median, mode, and range of times for the second week? Student Hours
Bob 19
James 10
Karen 15
Rosario 17
Antoine 10
Julio 16
Maria 13
The answer is the mean, mode, and median increases by 4, the range of times is the same.
Week 1: Week 2: Student - Hours Student - Hours<span> Bob 19 </span>Bob 23<span> James 10 </span>James 14<span> Karen 15 </span>Karen 19<span> Rosario 17 </span>Rosario 21<span> Antoine 10 </span>Antoine 14<span> Julio 16 </span>Julio 20<span> Maria 13 </span>Maria 17<span>
The mean is the sum of all values divided by the number of values: Week 1: (19 + 10 + 15 + 17 + 10 + 16 + 13)/7 = 100/7 = 14.28 Week 2: (23 + 14 + 19 + 21 + 14 + 20 + 17)/7 = 128/7 = 18.28 The difference in means between Week 2 and Week 1 is 4 (18.28 - 14.28 = 4)
The median is the middle value. To calculate, first rearrange values from the lowest to the highest and then find the middle value: Week 1: 10, 10, 13, 15, 16, 17, 19 - The median is 15. Week 2: 14, 14, 17, 19, 20, 21, 23 - The median is 19. The difference in medians between Week 2 and Week 1 is 4 (19 - 15 = 4)
The mode is the value that occurs most frequently. </span>Week 1: 10, 10, 13, 15, 16, 17, 19 - The mode is 10. Week 2: 14, 14, 17, 19, 20, 21, 23 - The mode is 14. The difference in modes between Week 2 and Week 1 is 4 (14 - 10 = 4)
The range of times is the difference between the highest and the lowest value. Week 1: 10, 10, 13, 15, 16, 17, 19 - The range of times is 9 (19 - 10 = 9). Week 2: 14, 14, 17, 19, 20, 21, 23 - The median is 9 (23 - 14 = 9). The difference in the ranges of times between Week 2 and Week 1 is 0 (9 - 9 = 0)
The best and most correct answer among the choices provided by your question is the fourth choice or letter D.
Octahedron (8) is a <span>polyhedron has more faces than a hexahedron, but fewer faces than an dodecahedron.</span>
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