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Hoochie [10]
3 years ago
7

X-1=5x+3x-8help this confused child

Mathematics
1 answer:
alexira [117]3 years ago
4 0
X-1= 5x+3x-8

Combine like terms
x-1= 8x-8

Our goal is to isolate x by cancelling out other numbers.
Subtract x from both sides
x-1-x= 8x-x-8
-1= 7x-8

Add 8 to both sides
7=7x

Divide both sides by 7
1=x

Final answer: x=1
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A city planner wants to build a road perpendicular to D Street. What is the slope of the new road?
Romashka-Z-Leto [24]

Answer:

The slope of the new road is 0.

Step-by-step explanation:

  • the slope of d street line is tan(90)

[if the angle made by a line with x axis is \alpha then, the slope of that line will be tan(\alpha) ]

  • here, the angle made by the d street line with x axis is 90 degrees.
  • if a road is to be built which is perpendicular to d street , it should make 0 degrees i.e, it should be parallel to x axis .
  • so, the slope of new road will be tan(0) = 0
7 0
2 years ago
Read 2 more answers
The cost C (in dollars) to participate in a ski club is given by the literal equation C=85x+60, where X=C/85-12/17 is the number
dybincka [34]

Given:

The cost C (in dollars) to participate in a ski club is given by,

\begin{gathered} C=85x+60 \\ (or) \\ x=\frac{C}{85}-\frac{12}{17} \end{gathered}

Where x is the number of ski trips we take.

To find:

The number of ski trips when a total cost of $315 and $485 is spent.

Explanation:

Substituting C = 315 in the given equation we get,

\begin{gathered} x=\frac{315}{85}-\frac{12}{17} \\ x=\frac{315-60}{85} \\ x=\frac{255}{85} \\ x=3\text{ ski trips} \end{gathered}

Substituting C = 485 in the given equation we get,

\begin{gathered} x=\frac{485}{85}-\frac{12}{17} \\ x=\frac{485-60}{85} \\ x=\frac{425}{85} \\ x=5\text{ ski trips} \end{gathered}

Thus,

If we spend a total cost of $315, we can take 3 ski trips.

If we spend a total cost of $485, we can take 5 ski trips.

Final answer:

• If we spend a total cost of $315, we can take 3 ski trips.

,

• If we spend a total cost of $485, we can take 5 ski trips.

8 0
9 months ago
Solve the systems of equations by the elimination method:<br> -2x + 2y = 2<br> -4y - 2x = -22
bekas [8.4K]
Answer:

(3,4)

Step by step explanation:
7 0
3 years ago
What is the range of the graph above?
Juli2301 [7.4K]
There is no graph for us to see
5 0
2 years ago
Solve (x + 5)^(3/2)= (x - 1)^3
IRINA_888 [86]

Answer:

  x = 4

Step-by-step explanation:

For an equation of this sort, my first step is to rewrite it so the solutions are the x-intercepts of the graph:

  (x +5)^(3/2) -(x +1)^3 = 0

The graph is attached. The one real solution is x=4.

__

The solution method for something like this is necessarily ad hoc. Here, it appears that progress can be made by raising both sides of the equation to the 2/3 power:

  ((x +5)^(3/2))^(2/3) = ((x -1)^3)^(2/3)

  x +5 = (x -1)^2

Now, you have an ordinary quadratic that can be solved using any of the usual methods.

  x^2 -2x +1 = x +5 . . . . swap sides, expand the square

  x^2 -3x -4 = 0 . . . . . . put in standard form

  (x -4)(x +1) = 0 . . . . . . factor

The solutions to this are ...

  x = 4, x = -1 . . . . . . . values of x that make the factors zero

__

To see if either of these solutions is extraneous, we can check them:

  (4 +5)^(3/2) = (4 -1)^3 . . . . . substitute 4 for x

  9^(3/2) = 3^3 . . . . . . . . . true

  (-1 +5)^(3/2) = (-1 -1)^3 . . . . . substitute -1 for x

  4^(3/2) = (-2)^3

  8 = -8 . . . . . . . . . . . false; x = -1 is extraneous

The solution is x = 4.

_____

<em>Additional comment</em>

You can eliminate the x=-1 "solution" by considering the domains of the left- and right-side expressions. The 3/2 power is equivalent to the square root of the cube. That will generally only be defined for non-negative values (x ≥ -5). The cube on the right will only be positive for x > 1, so the practical domain of this equation is x ≥ 1.

5 0
2 years ago
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