By knowing that <em>water</em> outflow is <em>stable</em> and the known geometry, the <em>draining</em> time of the rectangular tank is equal to a time of a minute and 36 seconds.
<h3>How to determine the draining time of a rectangular tank</h3>
In this question we must determine the <em>draining</em> time of a tank whose dimensions are known and whose <em>water</em> outflow is <em>stable</em>. The <em>draining</em> time is equal to the volume of the <em>rectangular</em> tank divided by <em>outflow</em> rate:
V = (1.2 m) · (0.8 m) · (0.5 m)/(0.3 m³/min)
V = 1.6 min
By knowing that <em>water</em> outflow is <em>stable</em> and the known geometry, the <em>draining</em> time of the rectangular tank is equal to a time of a minute and 36 seconds.
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Answer:
A) perimeter = 3 + 3 + 8 + 8 = 22 units
B) area = 3 x 8 = 24 units²
Step-by-step explanation:
Answer:
24.76 mine
Step-by-step explanation:
The first thing is to calculate the area of the region, which we can calculate since we have the density and the population. The area would be the quotient between population and density:
260000/135 = 1925.93
The area would be 1925.93 square mine
We know that the area is given by:
A = pi * r ^ 2
we solve to r
r ^ 2 = A / pi
r ^ 2 = 1925.92 / 3.14
r ^ 2 = 613.3
r = 24.76
the radius is equal to 24.76 mine
Answer:
67
Step-by-step explanation:
To solve this question ( that is to know the number), we must interpret the statement mathematically. Let the unknown number be T then,
547% of T = 366.49
547 * T/100 = 366.49
547T = 36646
T = 36649/547
= 67
It means that 547% of 67 gives 366.49
