8x + 4y = 20
4y = 20 - 8x
y = 5 - 2x
Let us assume the number of movies for ehich the cost of both companies becomes the same = x
Then
55 + 4x = 110
4x = 110 - 55
4x = 55
x = 55/4
= 13.75
So
The number <span>number of movies for which the cost of Carl's cable company is less than the cost of Teleview = 13.
I hope the procedure is clear enough for you to understand and this is the answer that you were actually looking for.</span>
Answer:
y=-2x-13
Step-by-step explanation:
y-y1=m(x-x1)
y-(-13)=-2(x-0)
y+13=-2x
y=-2x-13
The correct answer is c but i am not sure
Let the fist integer be x, the second is x+20
the product of the numbers is:
x(x+20)
the sum of the numbers is:
x+x+20=2x+20
the sum of the above operations will give us:
2x+20+x^2+20x=95
x^2+22x+20=95
this can be written as quadratic to be:
x^2+22x-75=0
solving the above we get:
x=3 and x=-25
but since the integers should be positive, then x=3
the second number is x+20=3+20=23
hence the numbers are:
3 and 23
