If a bag contains white, black and red balls only and the probability of getting a white ball is 3/10 and the probability of a black ball is 2/5 then the probability of getting red balls is 3/10.
Given that a bag contains white, black and red balls only and the probability of getting a white ball is 3/10 and the probability of a black ball is 2/5.
We are required to find the probability of getting red balls.
Probability=Number of items/Total items
Probability of getting red balls=1-(Probability of getting white balls +Probability of getting black balls)
=1-(3/10+2/5)
=1-7/10
=3/10
Hence if a bag contains white, black and red balls only and the probability of getting a white ball is 3/10 and the probability of a black ball is 2/5 then the probability of getting red balls is 3/10.
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Answer:
Step-by-step explanation:
we have
----> The degree of this polynomial is 1 (linear equation)
Remember that
The zero of the polynomial is the value of x when the value of f(x) is zero
so
For f(x)=0
solve for x
----> the zero of the polynomial or x-intercept
9 × n - 20 = 16
9n - 20 = 16
+ 20
9n = 36
÷ 9
n = 4
Hope this helps! :)
Answer:
40%
Step-by-step explanation:
18+12+20=50
20/50×100=
40%
A) <DAE = 180-126 = 54
b) <EBC = 90 - 48 = 42
c) <BAE = 180-48-54=78
