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il63 [147K]
3 years ago
15

The water level In a plastic pool changed by the -8 gallons each hour due to a small hole in the bottom after 6 hours the pool c

ontained 132 gallons how much water was in the pool originally
Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

180 gallons

Step-by-step explanation:

Each hour, 8 gallons were lost. Thus, in 6 hours,

6 * 8 = 48 gallons were lost

After 6 hours, 132 gallons remained, so before this 6 hours, there were more 48 gallons in it. Thus,

Original amount was 132 + 48 = 180 gallons

Originally, 180 gallons of water was in the pool

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3 years ago
Which of the equations will be a true statement if p=10 power of 3? Select all that apply.
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Answer:

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Step-by-step explanation:

7 0
3 years ago
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Suppose that 40 deer are introduced in a protected wilderness area. The population of the herd
Scorpion4ik [409]

The horizontal asymptote of the function is the minimum number of deer in the area.

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\mathbf{f(x) = \frac{40 + 2x}{1 + 0.05x}}

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\mathbf{f(x) = \frac{40(1 + 0.05x)}{1 + 0.05x}}

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\mathbf{f(x) = 40}

Hence, the equation of horizontal asymptote is:

\mathbf{y = 40}

The horizontal asymptote means that, the number of deer will never be less than 40

Read more about horizontal asymptotes at:

brainly.com/question/4084552

8 0
2 years ago
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A = s^2

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3 years ago
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