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il63 [147K]
3 years ago
15

The water level In a plastic pool changed by the -8 gallons each hour due to a small hole in the bottom after 6 hours the pool c

ontained 132 gallons how much water was in the pool originally
Mathematics
1 answer:
vlada-n [284]3 years ago
5 0

Answer:

180 gallons

Step-by-step explanation:

Each hour, 8 gallons were lost. Thus, in 6 hours,

6 * 8 = 48 gallons were lost

After 6 hours, 132 gallons remained, so before this 6 hours, there were more 48 gallons in it. Thus,

Original amount was 132 + 48 = 180 gallons

Originally, 180 gallons of water was in the pool

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melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

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The common ratio (r) is calculated as:

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Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

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