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2 years ago

Simplify completely 12 times x to the third power minus 4 times x to the 2nd power plus 8 times x all over negative 2 times x.

Mathematics

1 answer:

Rudik [331]2 years ago

7 0

(12x^3-4x^2+8x)/2x

Just divide all the coefficients by -2 and take away an x from all of them.

It is the second one from the top.

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3x=15-6y in slope intercept form

sdas [7]

Answer: y= -1/2x + 5/2

Step-by-step explanation:

3x = 15 -6y

+6y + 6y

3x +6y =15

-3x -3x

6y= 15-3x divide both sides by 6

y= 15/6 - 3/6x

in slope intercept form us y= -3/6x + 15/6 in simplest form is y= -1/2x + 5/2

3 0

3 years ago

Use the image below to describe at least three different ratios, written in simplest form. Include at least one part-to-part rat

9966 [12]

The different ratios are 2 : 7, 2 : 9 and 7 : 9

<h3>How to determine the ratio?</h3>

The statement is given as:

8 out of 36 squares unfilled

This means that:

There are 36 squares
8 are unfilled
28 are filled

The part-to-part ratio is represented as:

Ratio = Unfilled : Filled

This gives

Unfilled : Filled = 8 : 28

Simplify

Unfilled : Filled = 2 : 7

The part-to-whole ratios are represented as:

Ratio = Unfilled : Total

Ratio = Filled : Total

So, we have:

Unfilled : Total = 8 : 36

Filled : Total = 28 : 36

Simplify

Unfilled : Total = 2 : 9

Filled : Total = 7 : 9

Hence, the different ratios are 2 : 7, 2 : 9 and 7 : 9

Read more about ratio at:

brainly.com/question/2328454

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6 0

1 year ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$