The answer is 7/5
please see the attached picture for full solution
Hope it helps
Good luck on your assignment
Answer:
A = 1701,38 ft²
Dimensions :
x (north and south sides ) = 38.89 ft
y ( east and west sides ) = 43,75 ft
Step-by-step explanation:
North and south (sides of same length) equal "y" cost (4 + 5 ) = 4,5 $/ft²
East and west (sides of same length) equal "x" cost ( 3 + 5 ) = 4 $ /ft²
Equation of cost is
C = Cost of (north + south ) + Cost (east + west)
C = 2 * 4,5 * x + 4*2* y
C = 9x + 8y
700 = 9x + 8y ⇒ y = ( 700- 9x)/ 8
A = x*y
A(x) = x * ( 700 - 9x ) /8
A(x) = ( 700 x -9x²) / 8 A´(x) = ( 700 - 18 x )/ 8 A´(x) = 0
( 700 - 18 x )/ 8 = 0 ⇒ 700 - 18 x = 0 ⇒ x = 700/18
x = 38.89 ft
y = ( 700 - 9x )/8 ⇒ y = 349.99 / 8 ⇒ y = 43.75
And maximum ara is
A = x*y A = 38.89 * 43.75 = 1701,38 ft²
Answer:
622.13 square units
Step-by-step explanation:
Area of the composite figure = area of parallelogram + area of circle
Note: 2 semicircles = 1 full circle
Area of the figure = a*h + πr²
Where,
a = 22
h = 11
r = ½ of 20 = 10
Plug in the value into the equation
Area = 22*11 + π*11²
Area = 242 + π*121
Area = 622.13271108 ≈ 622.13 square units (nearest tenth)
Answer:
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The general matrix representation for this transformation would be:
![\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Solving the matrix product you have that the members of the result matrix are:
3x+4y = a*x + c*y
x - 2y = b*x + d*y
So the matrix A should be:
![\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D)
