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Maksim231197 [3]
4 years ago
9

On a blueprint, the scale indicates that 7 cm represent 16 ft. What is the length of a room that is 9.8 cm long and 5 cm wide on

the blueprint?
Mathematics
2 answers:
Ira Lisetskai [31]4 years ago
3 0
The room is 22.4 feet long

7cm=16ft
9.8cm=?ft

  7cm       9.8cm
______=______
  16ft          x ft

Cross multiply
7x=156.8
divide both sides by 7
x=22.4 ft


Ksenya-84 [330]4 years ago
3 0

Answer:

The length of a room that is 9.8 cm long and 5 cm wide on the blueprint is:

22.4 ft. long and 11.43 ft. wide

Step-by-step explanation:

On a blueprint, the scale indicates that 7 cm represent 16 ft.

  1 cm represents 16/7 ft.

9.8 cm represents

\dfrac{16\times 9.8}{7}\\\\=22.4ft.

5 cm represents

 \dfrac{16\times 5}{7}\\\\=11.43ft.

Hence,  the length of a room that is 9.8 cm long and 5 cm wide on the blueprint is:

22.4 ft. long and 11.43 ft. wide

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Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

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The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

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Z = \frac{X - \mu}{\sigma}

Z = \frac{590 - 502}{115}

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Z = 0.76 has a p-value of 0.7764.

X = 400:

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58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

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