Hope this helps you! (and I'm right LOL)
Answer:
First we will split trapezium on two geometric figure.
One is rectangle and the second is right triangle.
When we subtract 11-4=7cm we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.
We will use Pythagorean theorem to find the second cathetus b
b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>
AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm
AC=18.1cm
Good luck!!
The algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z
<h3>How to write an algebraic expression for the word phrase "the product of a number and 3" as a variable expression?</h3>
The word phrase is given as:
"the product of a number and 3"
Represent the number with z
So, the word phrase can be rewritten as:
"the product of a number z and 3"
The product of a number z and 3 is represented as:
z * 3
When evaluated,, the expression becomes
z * 3 = 3z
Hence, the algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z
Read more about algebraic expression at
brainly.com/question/4344214
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A. 7.1 b.idk sorry c.74,160
