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Stells [14]
2 years ago
11

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each sequence to its appropriate re

cursively defined function. Recursively Defined Function Tile One: f(1) = -18 f(n) = 2 · f(n - 1) for n = 2, 3, 4, ... Tile Two: f(1) = 11 f(n) = f(n - 1) + 22 for n = 2, 3, 4, ... Tile Three: f(1) = -18 f(n) = f(n - 1) + 22 for n = 2, 3, 4, ... Tile Four: f(1) = 11 f(n) = 3 · f(n - 1) for n = 2, 3, 4, ... Tile Five: f(1) = -18 f(n) = 6 · f(n - 1) for n = 2, 3, 4, ... Tile Six: f(1) = -18 f(n) = f(n - 1) + 21 for n = 2, 3, 4, ... Sequences: Recursively 11, 33, 55, 77, ... -18, 3, 24, 45, ... -18, -108, -648, -3,888, ...
Mathematics
2 answers:
sp2606 [1]2 years ago
8 0

Answer:

2,3,4

Step-by-step explanation:

Allushta [10]2 years ago
3 0

Answer:

2, 3, 4,

Step-by-step explanation:

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Klio2033 [76]
Well you find how much the error was and divide it by the amount he predicted.
30/230= 0.13 0.13=13%
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3 years ago
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Partial quotients of 3 divided by 225
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The answer is 75 you could do long division and that will get you the answer.
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3 years ago
Which point is NOT part of the solution set?
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8 0
2 years ago
Simplify the expression csc(-x)/1+tan^2x)
Charra [1.4K]
Assuming ya meant \frac{csc(-x)}{1+tan^2(x)}

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos


for the pythaogreaon identity
cos^2(x)+sin^2(x)=1
divide both sides by cos^2(x)
1+tan^2(x)=sec^2(x) since \frac{sin(x)}{cos(x)}=tan(x)
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recall that csc(x)=\frac{1}{cos(x)}
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)
so we get

\frac{csc(x)}{sec^2(x)}
decompose them into \frac{1}{cos(x)} and \frac{1}{sin^2(x)} to get \frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}
multiply by \frac{sin^2(x)}{sin^2(x)} to get
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we can furthur simlify to get
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the expression simplifies to tan(x)sin(x)
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3 years ago
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