The restrictions on the variable of the given rational fraction is y ≠ 0.
<h3>The types of numbers.</h3>
In Mathematics, there are six (6) common types of numbers and these include the following:
- <u>Natural (counting) numbers:</u> these include 1, 2, 3, 4, 5, 6, .....114, ....560.
- <u>Whole numbers:</u> these comprises all natural numbers and 0.
- <u>Integers:</u> these are whole numbers that may either be positive, negative, or zero such as ....-560, ...... -114, ..... -4, -3, -2, -1, 0, 1, 2, 3, 4, .....114, ....560.
- <u>Irrational numbers:</u> these comprises non-terminating or non-repeating decimals.
- <u>Real numbers:</u> these comprises both rational numbers and irrational numbers.
- <u>Rational numbers:</u> these comprises fractions, integers, and terminating (repeating) decimals such as ....-560, ...... -114, ..... -4, -3, -2, -1, -1/2, 0, 1, 1/2, 2, 3, 4, .....114, ....560.
This ultimately implies that, a rational fraction simply comprises a real number and it can be defined as a quotient which consist of two integers x and y.
<h3>What are
restrictions?</h3>
In Mathematics, restrictions can be defined as all the real numbers that are not part of the domain because they produces a value of 0 in the denominator of a rational fraction.
In order to determine the restrictions for this rational fraction, we would equate the denominator to 0 and then solve:
23/7y;
7y = 0
y = 0/7
y ≠ 0.
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Complete Question:
State any restrictions on the variables 23/7y
<em>Your question is not well presented</em>
Question:
What is the solution to the linear equation?
Answer:
Step-by-step explanation:
Given
Required
Simplify
Add 
to both sides
Subtract 
from both sides
Take LCMs
Multiply both sides by 6
Divide both sides by -3
Answer:
If B is between A and C, AB = x, BC = 2x + 2, and AC = 14, find the value of x. Then find AB and BC.
Step-by-step explanation:
AB=x
BC = 2x + 2BC=2x+2
AC =14AC=14
Required
Determine x, AB and BC.
Since B is between A and C;
AB + BC = ACAB+BC=AC
Substitute x for AB; 2x + 2 for BC and 14 for AC
x + 2x + 2 = 14x+2x+2=14
3x + 2 = 143x+2=14
Collect Like Terms
3x = 14 - 23x=14−2
3x = 123x=12 '
x = \frac{12}{3}x=
3
12
x = 4x=4
Substitute 4 for x in
AB = xAB=x
BC = 2x + 2BC=2x+2
AB = 4AB=4
BC = 2(4) + 2BC=2(4)+2
BC = 8 + 2BC=8+2
BC = 10BC=10
For example if you have multiple numbers with the letter a at the end you will want to add. 7a + 8a would be 15a. Same for subtraction. If you have an equation with multiple letters. For example 4a+9b it will stay 4a and 9b. Make sure to do pemdas
No, it would be the same because 6*4=24 then divide that by four and get 6
