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3 years ago

What are the three factors needed for Newton’s Second Law?

Physics

1 answer:

Anastasy [175]3 years ago

5 0

Answer:

the weight of the object, the force of gravity acting on said object, and the mass of the object are needed for Newton's second law of motion.

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Which statement defines an ore? Rock broken down to become part of the topsoil. Rock dug out from the earth to use in constructi

Anika [276]

Rock dug out from the deep inside earth and refined.

Explanation:

Ores are usually rocks dug out from deep within the earth and refined.

An ore is an aggregate of metalliferous minerals with gangue that can be won at profit under current economic conditions.

Ores are rocks and rocks can be ores if they contain viable economic minerals.

They are usually naturally formed and they contain different minerals.

For example cassiterite is a known ore of tin.

Learn more:

Rocks brainly.com/question/2817889

#learnwithBrainly

5 0

3 years ago

Read 2 more answers

Recall that if a line is parallel to the vector v and passes through the point P0, which is the tip of the position vector r0, t

Elenna [48]

Answer:

The vector equation of the line is

$\overrightarrow{r}=+t$

Parametric equations for given line are

$x=7+t\\y=-8+6t\\z=3-13t$

Explanation:

The vector equation of the line is given by

$r(t) = r_{o} + tv$

r₀ = (7, -8, 3)

v = (1, 6, -13)

At these points the vector equation for this line is:

$\overrightarrow{r}=\overrightarrow{r_{o}}+t\overrightarrow{v}\\\overrightarrow{r}=+t$

Parametric equations for given line are

$x=7+t\\y=-8+6t\\z=3-13t$

8 0

3 years ago

In terms of saturation (unsaturated, saturated, super-saturated). How would you classify the following?

miskamm [114]

Answer:

1. A NaCl solution with a concentration of 50g/100mL of water at 40°C: The NaCl solution with a given concentration is saturated at this temperature .As the temperature increases the solution will more dissolves.

2. A sugar solution with a concentration of 200g/100mL of water at 40°C: The sugar solution with a given concentration is saturated at this temperature. As the temperature increases the solution will more dissolves.

3. A sugar solution with a concentration of 240g/100mL of water at 40°C: The sugar solution with a given concentration is saturated at given temperature.

7 0

3 years ago

A cable is 100-m long and has a cross-sectional area of 1.0 mm2. A 1000-N force is applied to stretch the cable. Young's modulus

Blizzard [7]

Answer:

1 m

Explanation:

L = 100 m

A = 1 mm^2 = 1 x 10^-6 m^2

Y = 1 x 10^11 N/m^2

F = 1000 N

Let the cable stretch be ΔL.

By the formula of Young's modulus

$Y=\frac{F\times L}{A\times\Delta L}$

$\Delta L=\frac{F\times L}{A\times\Y}$

$\Delta L=\frac{1000\times 100}{10^{-6}\times10^{11}}$

ΔL = 1 m

Thus, the cable stretches by 1 m.

4 0

3 years ago

Andrea's near point is 20.0 cm and her far point is 2.0 m. Her contact lenses are designed so that she can see objects that are

Shalnov [3]

Answer:

the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

Explanation:

Given the data in the question,

near point = 20 cm

far point = 2 m = 200 cm

Now, for an object that is infinitely far away, the image is at is its far point.

so using the following expression, we can determine the focal length

1/f = 1/i + 1/o

where f is the focal length, i is the image distance and o is the object distance.

here, far point i = 2 m = 200 cm and v is ∞

so we substitute

1/f = 1/(-200 cm) + 1/∞

f = -200 cm

Also, for object at its closest point, the image appear at near point,

1/f = 1/i + 1/o

we make o the subject of formula

o = ( i × f ) / ( i - f )

given that near point i = 20 cm

we substitute

o = ( -20 × -200 ) / ( -20 - (-200) )

o = 4000 / 180

o = 22.2 cm

Therefore, the closest distance that she can see an object clearly when she wears her contacts is 22.2 cm

4 0

3 years ago