Answer:
v₂ = 70 m / s
Explanation:
For this exercise let's use Bernoulli's equation
where subscript 1 is for the top of the mountain and subscript 2 is for Tuesday's level
P₁ + ½ ρ v₁² + ρ g y₁ = P₂ +1/2 ρ v₂² + ρ g y₂
indicate that the pressure in the two points is the same, y₁ = 250 m, y₂ = 0 m, the water in the upper part, because it is a reservoir, is very large for which the velocity is very small, we will approximate it to 0 (v₁ = 0), we substitute
ρ g y₁ = ½ ρ v₂²
v₂ =
let's calculate
v₂ = √( 2 9.8 250)
v₂ = 70 m / s
Answer: 900
Explanation: Force equals mass x acceleration F=M×A
Answer:
A.
Explanation:
NEAR THE CENTER OF TECTONIC PLATES.
Answer:
The observer sees the space-probe 9.055m long.
Explanation:
Let
be the length of the space-probe when measured at rest, and
be its length as observed by an observer moving at velocity
, then

Now, we know that
and
, and putting these into
we get:


Thus, an observer moving at 0.95c observes the space-probe to be 9.055m long.